CHEM 110 determining Ka for pH indicators

.pdf

School

University of Nebraska, Lincoln *

*We aren’t endorsed by this school

Course

110L

Subject

Economics

Date

May 13, 2024

Type

pdf

Pages

5

Uploaded by HighnessBadger901 on coursehero.com

Experiment 6 Determining Ka for pH Indicator Total Points: 67 Student’s Name: Parker Gould Lab Section: 503 Your report must include the following: - Data Tables 1 and 2 - Copies of the information you posted on Canvas (both the titration curve and data table summary) - Section Results Tables 1 and 2 - Post-lab Questions NOTE: You must show your work for all calculations; no work, no credit. Data Table 1 (5 pts) Buret Reading (mL) pH Buret Reading (mL) pH 0.0 4.90 15.0 8.59 0.5 4.96 15.5 8.74 1.0 4.99 16.0 8.88 1.5 5.02 16.5 8.96 2.0 5.08 17.0 9.04 2.5 5.15 17.5 9.06 3.0 5.20 18.0 9.13 3.5 5.28 18.5 9.15 4.0 5.33 19.0 9.18 4.5 5.45 19.5 9.19 5.0 5.53 20.0 9.22 5.5 5.62 20.5 9.20 6.0 5.72 21.0 9.22 6.5 5.79 21.5 9.23 7.0 5.89 22.0 9.23 7.5 6.0 22.5 9.24 8.0 6.06 23.0 9.27 8.5 6.15 23.5 9.20 9.0 6.25 24.0 9.31 9.5 6.33 24.5 9.32 10.0 6.42 25.0 9.33 10.5 6.51 25.5 9.36 11.0 6.60 26.0 9.37 11.5 6.73 26.5 9.38 12.0 6.85 27.0 9.38 12.5 7.13 27.5 9.39 13.0 7.36 28.0 9.40 13.5 7.65 28.5 9.41
Experiment 6 Determining Ka for pH Indicator Total Points: 67 14.0 7.98 29.0 9.42 14.5 8.25 29.5 9.43 30.0 9.44 Data Table 2 (10 pts) pH Absorbance Determined K a Explanation if K a NOT Included in Average 8.24 0.638 6.67 0.435 3.7x10^-7 5.35 0.211 2.2x10^-6 4.37 0.144 1.2x10^-5 4.04 0.090 1.5x10^-5 3.90 0.089 2.0x10^-5 3.76 0.074 2.3x10^-5 3.67 0.065 2.4x10^-5 3.66 0.044 1.6x10^-5 Data Outlier Qcalc > Qtable = 0.512>0.376 Average K a (3 pts) 1.4x10^-5 Show Q test calculation if any test performed and include a justification for why you used the Q test of why you did not use the Q test (5 pts): data point did not correlate with the trend of the data points. Ka= [10^-pH](A) / (Aref-A) 10^-6.67 (0.435) / (0.638-0.435) = 3.7x10^-7 Gap= 2.2x10^-6 - 3.7x10^-7 = 1.83x10^-6 2.4x10^-5 - 1.6x10^-5 = 8.0x10^-6 (Bigger) 8.0x10^-6 / (1.6x10^-5 - 3.7x10^-7) = 0.512 Qcalc > Qtable —> 0.512>0.376
Experiment 6 Determining Ka for pH Indicator Total Points: 67 Section Results Table 1 – Titration Curve Method In the table below, enter at K a values determined by the titration method from all groups in your lab section. Calculate the overall average K a . Determined K a – Titration Method (5 pts) Explanation If Determined K a Excluded from Average 7.76x10^-7 1.62x10^-6 1.82x10^-6 2.69x10^-6 4.90x10^-6 5.50x10^-5 Data seems to be skewed resulting in the wrong type of curve in the graph Qcalc> Qtable Average K a – Titration Method (3 pts) 2.36x10^-6 Show work if Q test performed and include a justification for why you used the Q test or why you did not use the Q test (5 pts): Gap= 1.62x10^-6 - 7.76x10^-7 = 8.44x10^-7 5.50x10^-5 - 4.90x10^-6 = 5.01x10^-5 (bigger) 5.01x10^-5 / (55.50x10^-5 - 7.76x10^-7) = 0.924 Qcalc>Qtable Section Results Table 2 – Spectrophotometric Method In the table below, enter all average K a values determined by the spectrophotometric method from all groups in your lab section. Calculate the overall average K a . Determined Average Ka – Spectrophotometric Method (5 pts) 1.4x10^-5 0.024 1.11x10^-5 6.37x10^-6
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help