. 12.28 A slab of ice floats on a freshwater lake. What minimum volume must the slab have for a 65.0-kg woman to be able to stand on it without getting her feet wet? Buoyancy force= weight of water displaced = vol. x density x g (Wt of ice +women) 0.81 m³

. 12.28 A slab of ice floats on a freshwater lake. What minimum volume must the slab have for a 65.0-kg woman to be able to stand on it without getting her feet wet? Buoyancy force= weight of water displaced = vol. x density x g (Wt of ice +women) 0.81 m³

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter11: Fluid Statics

Section: Chapter Questions

Problem 46PE: (a) What is the density of a woman who floats in freshwater with 4.00% of her volume above the...

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Question

I need help with this problem and an explanation of why its the answer described below:

(0.81 m^3 is the answer but I need an explanations as to why it's the answer.)

.
12.28 A slab of ice floats on a freshwater lake. What minimum
volume must the slab have for a 65.0-kg woman to be able to stand
on it without getting her feet wet?
Buoyancy force= weight of water displaced = vol. x density x g
(Wt of ice +women)
0.81 m³

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