1 0 1 ~EHEMMEHO V 4 2 0 Let v = 1 0 4 O C.S O d. {v, - and S= { v₁ O a. (v. v₂} 1 2 9 O b. {V₁, V 3 } 1 v₁} 4 . 1 1 V 3 4 ○e. { v₁ • V 2• V3} 0 0 and v }. A basis for span (S) is 4 1 1 6
1 0 1 ~EHEMMEHO V 4 2 0 Let v = 1 0 4 O C.S O d. {v, - and S= { v₁ O a. (v. v₂} 1 2 9 O b. {V₁, V 3 } 1 v₁} 4 . 1 1 V 3 4 ○e. { v₁ • V 2• V3} 0 0 and v }. A basis for span (S) is 4 1 1 6
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.1: Rectangular Coordinate Systems
Problem 16E
Related questions
Question
Transcribed Image Text:1
0
1
~EHEMME-B
V
4
2
0
Let v =
O a. (v.
1
and S= { v₁
1
O C.S
O d. {v,
1
0
.
4
9
O b. {v₁ V3 }
9
1
v₂}
2
v₁}
4
1
V
3
○e. {V₁ · V2 · V3 }
0
0
and v
}. A basis for span (S) is
4
4
1
1
6
Transcribed Image Text:Select all subapaces of R³
a.
1 3
col0 1)
27
b. {(x+2,x-1, z) / x and z are arbitrary real numbers }
OC.
3
span{ |}
1
d. {(2x, 3x, 4x) / x in R}
e. {(x,y,z) in R³/x+y +z = 0}
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