(1) A rigid bar (OA)with mass m and length L is simply supported at one end and free at the other end .A lumped mass M fixed at the end of A is subjected to a vertical harmonic excitation f(t). Two springs(k) are connected at the length a and b of the bar. Please calculate the natural frequency w and response vibration of the system. (Figure 1) Note: m=10kg, L=1 m, a=0.25m, b=0.5m, k=5000N/m, M=50kg, f(t)=Fcost (F=500N, 22=1000rpm). The vibration is very small. a b k MA k m M Figure 1: Single Degree Vibration System f(t) A X

(1) A rigid bar (OA)with mass m and length L is simply supported at one end and free at the other end .A lumped mass M fixed at the end of A is subjected to a vertical harmonic excitation f(t). Two springs(k) are connected at the length a and b of the bar. Please calculate the natural frequency w and response vibration of the system. (Figure 1) Note: m=10kg, L=1 m, a=0.25m, b=0.5m, k=5000N/m, M=50kg, f(t)=Fcost (F=500N, 22=1000rpm). The vibration is very small. a b k MA k m M Figure 1: Single Degree Vibration System f(t) A X

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Consider the damped mass-spring system for mass of 1.5 kg, spring constant 10 N/m, damping 3 kg/s and an oscillating force 4.7 cos(@t) Newtons. That is, 1.5x" + 3x' + 10x = 4.7 cos(@t). What positive angular frequency o leads to maximum practical resonance? W = help (numbers) What is the maximum displacement of the mass in the steady state solution when the we are at practical resonance: C(@) = help
(1) A rigid bar (OA)with mass m and length L is simply supported at one end and free at the other end .A lumped mass M fixed at the end of A is subjected to a vertical harmonic excitation f(t). Two springs(k) are connected at the length a and b of the bar. Please calculate the natural frequency w and response vibration of the system. (Figure 1) Note: m=10kg, L=1 m, a=0.25m, b=0.5m, k=5000N/m, M=50kg, f(t)=FcosQt (F=500N, 2=1000rpm). The vibration is very small. a b k L MAA m M Figure 1: Single Degree Vibration System f(t) A X
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