1000 cm^3 of air at an initial pressure of 1.10 × 10^5 Pa and temperature of 300 K undergoes the following changes: heat the air at constant pressure until its temperature reaches 390 K and then compress the air isothermally until it returns to the initial volume of 1000 cm3 and finally allow the air to cool so that its final pressure is 1.10 × 10^5 Pa. i. Draw a P-V graph to represent the changes undergone by the air ii. Calculate the maximum volume of the air. iii. What is the maximum pressure of the air? iv. State how the net work done on the air for the whole process can be determined
1000 cm^3 of air at an initial pressure of 1.10 × 10^5 Pa and temperature of 300 K undergoes the following changes: heat the air at constant pressure until its temperature reaches 390 K and then compress the air isothermally until it returns to the initial volume of 1000 cm3 and finally allow the air to cool so that its final pressure is 1.10 × 10^5 Pa. i. Draw a P-V graph to represent the changes undergone by the air ii. Calculate the maximum volume of the air. iii. What is the maximum pressure of the air? iv. State how the net work done on the air for the whole process can be determined
Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Kreith, Frank; Manglik, Raj M.
Chapter6: Forced Convection Over Exterior Surfaces
Section: Chapter Questions
Problem 6.25P
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1000 cm^3 of air at an initial pressure of 1.10 × 10^5 Pa and temperature of 300 K undergoes the following changes: heat the air at constant pressure
until its temperature reaches 390 K and then compress the air isothermally
until it returns to the initial volume of 1000 cm3
and finally allow the air to cool so that its final pressure is 1.10 × 10^5 Pa.
i. Draw a P-V graph to represent the changes undergone by the air
ii. Calculate the maximum volume of the air.
iii. What is the maximum pressure of the air?
iv. State how the net work done on the air for the whole process can be
determined
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