2.70g of Zn (s) reacts with 50.0 mL of 1.00 M HCI solution to produce hydrogen gas according to the reaction. (R = 0.08206 L·atm-K-1•mol-1) Zn(s) + 2HCI (aq) = ZnCl2 (aq) + H2(g) a) calculate mole of Zn used in this reaction b) calculate mole of HCl used in this reaction c) calculate which reactant is a limiting reactant d) calculate mole of hydrogen gas formed e) calculate volume of H2 gas at STP in Liters that will be produced during the reaction

Introduction to General, Organic and Biochemistry
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2.70g of Zn (s) reacts with 50.0 mL of 1.00 M HCI solution to produce hydrogen gas according to the reaction. (R = 0.08206 L·atm-K-1•mol-1)
Zn(s) + 2HCI (aq) = ZnCl2 (aq) + H2(g)
a) calculate mole of Zn used in this reaction
b) calculate mole of HCl used in this reaction
c) calculate which reactant is a limiting reactant
d) calculate mole of hydrogen gas formed
e) calculate volume of H2 gas at STP in Liters that will be produced during the reaction
Transcribed Image Text:2.70g of Zn (s) reacts with 50.0 mL of 1.00 M HCI solution to produce hydrogen gas according to the reaction. (R = 0.08206 L·atm-K-1•mol-1) Zn(s) + 2HCI (aq) = ZnCl2 (aq) + H2(g) a) calculate mole of Zn used in this reaction b) calculate mole of HCl used in this reaction c) calculate which reactant is a limiting reactant d) calculate mole of hydrogen gas formed e) calculate volume of H2 gas at STP in Liters that will be produced during the reaction
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