3. Complete the following table: Fill in the mL used of the two starting materials (from the experimental procedure below) and calculate the moles of each species (show your work, include units). NOTE: Since glacial acetic acid contains water, you do not need to calculate the grams of this reagent; simply use the molarity given to calculate the moles of acid used in the procedure. Which will be the limiting reagent, acetic acid or isoamyl alcohol? Materials Molecular Weight (g/mol) Density (or Molarity) mL used Grams Moles acetic acid 60.05 17.4 M n/a isoamyl alcohol 88.15 0.809 * * * isoamyl acetate 130.19 0.876 *Calculate Theoretical yield of Isoamyl acetate in mL, g and moles (show your work, include units): Moles of isoamyl acetate: Grams of isoamyl acetate: Volume (mL) of isoamyl acetate:

EBK A SMALL SCALE APPROACH TO ORGANIC L
4th Edition
ISBN:9781305446021
Author:Lampman
Publisher:Lampman
Chapter20: Nucleophilic Substitution Reactions: Competing Nucleophiles
Section: Chapter Questions
Problem 8Q
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3. Complete the following table:
Fill in the mL used of the two starting materials (from the experimental procedure below) and
calculate the moles of each species (show your work, include units).
NOTE: Since glacial acetic acid contains water, you do not need to calculate the grams of this
reagent; simply use the molarity given to calculate the moles of acid used in the procedure.
Which will be the limiting reagent, acetic acid or isoamyl alcohol?
Materials
Molecular
Weight
(g/mol)
Density
(or
Molarity)
mL used
Grams
Moles
acetic acid
60.05
17.4 M
n/a
isoamyl alcohol
88.15
0.809
*
*
*
isoamyl acetate
130.19
0.876
*Calculate Theoretical yield of Isoamyl acetate in mL, g and moles (show your work, include units):
Moles of isoamyl acetate:
Grams of isoamyl acetate:
Volume (mL) of isoamyl acetate:
Transcribed Image Text:3. Complete the following table: Fill in the mL used of the two starting materials (from the experimental procedure below) and calculate the moles of each species (show your work, include units). NOTE: Since glacial acetic acid contains water, you do not need to calculate the grams of this reagent; simply use the molarity given to calculate the moles of acid used in the procedure. Which will be the limiting reagent, acetic acid or isoamyl alcohol? Materials Molecular Weight (g/mol) Density (or Molarity) mL used Grams Moles acetic acid 60.05 17.4 M n/a isoamyl alcohol 88.15 0.809 * * * isoamyl acetate 130.19 0.876 *Calculate Theoretical yield of Isoamyl acetate in mL, g and moles (show your work, include units): Moles of isoamyl acetate: Grams of isoamyl acetate: Volume (mL) of isoamyl acetate:
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