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- Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. CI H₂N OH • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. • Do not include counter-ions, e.g., Na+, I, in your answer. • In cases where there is more than one answer, just draw one. Sn [FDraw the line-angle formula of the enol formed in the following alkyne hydration reaction and then draw the structural formula of the carbonyl compound with which this enol is in equilibrium. -C=CH 1. (sia)2BH 2. NaOH/H₂O₂ an enol carbonyl compound • You do not have to consider stereochemistry. • Draw both the enol and the carbonyl forms. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. • Separate structures using the sign from the drop-down menu. ChemDoodleⓇ <Curved arrows are used to illustrate the flow of electrons. Follow the arrows and draw the intermediate and product in this reaction. Include all lone pairs. Ignore stereochemistry. Ignore inorganic byproducts. H-O :OCH₂ CH₂OH₂* :0: protonation Draw Intermediate CH3OH₂+ protonation CH3OH deprotonation loss of H₂O elimination 1 H₂C CH₂OH nucleophilic addition O-H Draw Intermediate CH3OH n deprotonatio Draw Product
- Consider a reaction where cis-but-2-ene is treated with OsO4 followed by NaHSO3/H2O. Draw the structure of one product that is formed in the reaction, including correct stereochemistry.Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. 0 OH CI + H₂N • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. • Do not include counter-ions, e.g., Na+, I, in your answer. In cases where there is more than one answer, just draw one. A ChemDoodle Activate WindowsQ2. When (CH3CH2)3CBR is added to CH3OH at room temperature, the major product is (CH30)C(CH2CH3)3 and a minor product is CH3CH3DC(CH2CH3)2. Propose a mechanism for the product that is formed by the substitution reaction. Use curved arrows to show the movement of electrons.
- Draw the alkene structure that produced the following compounds in a ozonolysis reaction as specified. 1. O3 2. (CH3)2S You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. In cases where there is more than one answer, just draw one.Draw the major organic product formed by reaction of 2-hexyne with the following reagent: BH3 followed by CH3COOH. . Consider E/Z stereochemistry of alkenes. In cases where there is more than one answer, just draw one. • If no reaction occurs, draw the organic starting material.МЕСНANISMS 1,2-epoxy-1-methylcyclopentane undergoes both acid-catalyzed and base-catalyzed opening of the epoxide ring to form two different products. > Using ethanol as the solvent and an appropriate acid, show the steps in the acid catalyzed mechanism, writing structures for all products of the steps. Circle the major product(s). > Using ethanol as the solvent and an appropriate base, show the steps in the base- catalyzed mechanism, writing structures for all products of the steps. Circle the major product(s). 1,2-epoxy-1-methylcyclopentane CH3
- Draw a structural formula of an alkene or alkenes (if more than one) that undergo acid-catalyzed hydration and without rearrangement give 2-methyl-2-butanol as the MAJOR product. You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. If more than one structure fits the description, draw them all. Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu.Consider a reaction where cis-but-2-ene is treated with a peroxy acid followed by OH- /H20. Draw the structure of one product that is formed in the reaction, including correct stereochemistry.The major product formed by addition of HBr to (CH3)₂C=CH-CH=C(CH3)₂ is the same at low and high temperature. Part 1 out of 2 Draw the structure of the major product. draw structure...