4. An unknown sample containing oxalic acid (H2C204) was analyzed using 0.2586 N NaOH. The following data were obtained in one of the trials of analysis Mass of unknown initial reading final reading 0.4658 g 10.10 mL - 30.90 mL a. What is the net volume of NaOH used in Liters 30.90ml 10-10m² = 20.8m² ? b. What is the molar mass of oxalic acid, H=1 g/mol, C=12 g/mol, O=16 g/mol H=1x2 =2 12x2=24 C 0=16x4 = 64 c. Calculate the % H2C2O4 in the sample ] 90 g/mol

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4. An unknown sample containing oxalic acid (H2C204) was analyzed using 0.2586 N
NaOH. The following data were obtained in one of the trials of analysis
Mass of unknown
initial reading
final reading
a. What is the net volume of NaOH used in Liters
30.90ml
-
0.4658 g
10.10 mL
30.90 mL
10-10m² = 20.8m² ?
b. What is the molar mass of oxalic acid, H=1 g/mol, C=12 g/mol, O=16 g/mol
H=1x2=2
7 90 g/mol
a
с 12x2=24
0=146x4 = 64
c. Calculate the % H2C2O4 in the sample
Transcribed Image Text:4. An unknown sample containing oxalic acid (H2C204) was analyzed using 0.2586 N NaOH. The following data were obtained in one of the trials of analysis Mass of unknown initial reading final reading a. What is the net volume of NaOH used in Liters 30.90ml - 0.4658 g 10.10 mL 30.90 mL 10-10m² = 20.8m² ? b. What is the molar mass of oxalic acid, H=1 g/mol, C=12 g/mol, O=16 g/mol H=1x2=2 7 90 g/mol a с 12x2=24 0=146x4 = 64 c. Calculate the % H2C2O4 in the sample
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