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A: (a) Density in CGS system of units is,
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Q: comparing
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A: Known Radius value RE =6.37 x 106 m
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Q: Calculate the average density of the following astronomical body: Mars.
A: The mass of the mars is 6.39×1023 kg and the volume of the mars is 16.318×1010 km3.
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Q: 12.8 (g?) (in)(cm?) (s)(lbm)(ft2) Convert to all SI units.
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Q: How do I find the density ?
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A: Given Mass = 38 kg Density = 340 kg/m3 We have to calculate the volume.
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Q: Density of iron is 1.49 g/ltr. Express it in, a. g/cm³ b. kg/m³
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Q: A piece of tin has a mass of 16.52 g and a volume of 2.26 cm³. What is the density of tin?
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Q: Q. 4: Convert density of 1000 kg/m³ into cm3.
A: Given density =1000 kg/m3 We know that, 1kg=1000g and 1m=100cm So, 1 kg/m3= 1000g/(100cm)3=10-3…
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- The pressure ata depth of 1.0 kmin the Pacific Oceanexceeds by 10 megaPascal. If a metallicalloy whose volumeat the surface is385 cm^3 islowered at a depthof 1.0 km, by howmuch does itsvolume (m^3)decrease?Bulk modulus ofalloy = 6.0 x 10 ^10Paaterials/gp/3411297783 RCES GRAWE REPORT 01 otion with friction practice.docx 1 /2 > 157% e - I ab] 1 (sha 25 box acrss w at constet seeedf Hoe much fore do vau exert the bax MK-2 0.1 2. klween yo5 talle and nendis oth bhat is gretesr hori2 fore eveyed whie t rerins 2.Ms 1s D4 710 crate accelesation of12:10 4G Not Secure - yslphysics.weebly.com the rod. odulus for metal = 1.0 x 10!l N m²² ) 30 of 32 Answer: 3.2×10-4 J EXERCISE 2 A hollow cylinder has length 50.0 cm, internal diameter 5.0 cm and external diameter 6.0 cm. A force of magnitude 1.0 kN acts at each end of cylinder so that the cylinder is being compressed. Determine the compression of cylinder. ( Young's modulus for the material of the Cylinder = 7.0x101º Nm-² ) Answer: 8.3×10-6 m EXERCISE 3 A wire of length 0.50 m is fixed horizontally between two supports separated by 0.50 m. When a mass of 8.0 kg hangs from the middle of the wire, the mid-point sags by 1.00 cm. The diameter of the wire is 2.8 mm. Calculate the Young's modulus of the wire. (Given g = 9.81 m s-2) Answer: 1.99 × 10* PuENG RCL 8. 7 4 CTAY 1 An alumnium cylinder has a diarncter o7 4) 4.80 cmo It has been hammered into a woll and its length, whjch can be seen arom Hhe will IS S-30 cm', An objest with a mass o7 seen 7rom hung From the edge og the mass o7 the modulus o7 aluminium iš 3.0Xl0NIm2 c) Calculate the shear stress on the cylınder b) (alculate the vertical dealechion o7 the ege o7 IS a mass 87 cylinder is nigligıble and the shear ylinder „Iz the' he cylinderDetermine the normal force N inside each bar Sa function of the external force P 1.5 m 2 m Probs. 1-40/41/421. The setup shown by the diagram below was used to calculate the force experienced by a small mass m situated at a distance r from the geometric center of a spherical shell with mass M, radius R, and a wall thickness of t. M = с dᎾ R 0 Rde A B Rsine r l r Ф p dF l If the mass is situated outside the spherical shell, the force can be calculated by integration from l = (r - R) (r+ R), as shown here: to l l=r+R R - 5 d² - T Gompert (1+²^²=R²) 21 SdF = Jae l=r-R m What would the limits of integration be if the mass were situated inside the spherical shell? Include a labeled diagram to represent this situation.During heavy lifting, a disk between spinal vertebrae is subjected to a 4750-N compression force. What us the created on the disk, in pascals, assuming that the disk has a uniform circular cross section 1.95 cm in radius? What deformation is produced, in centimeter, if disk is 0.95 cm thick and has a Young's modulus of 1.45x10^9 N/m^2?ength (L) and radius (r) is (Y). If the length is reduced to (L/3) and radius to (r/2), its Young's The ng s modulus of the wire of nodulus will be: 3Y a) (b) Y 4 c) Y (d) 12 YExplain the tem bulk modulus.by I m. They found the girths to be 6.3 m (at eround level), 5.4 m, 4.6 m, 4.4 m, 4.8 m and 3.9 m, and then the stone tapered to a point at a beight of 6 m. Assuming that the stone is made of basalt of density 2s00 kg/mand is nearly square in crosssection, find an approximation for the mass of the stone. Hint: Mass of an object m is given by the formula m = pV, where p is density and V is volume of the object.The equalion q a sHM progremive esliue SI aaue es y-0.4 Sin 100 TU. 40 units.? Caiceulate the cualielong tH speed of the walle.1. The setup shown by the diagram below was used to calculate the force experienced by a small mass m situated at a distance r from the geometric center of a spherical shell with mass M, radius R, and a wall thickness of t. M C dᎾ R 0 Rde A Rsine B r Ф dF Ф m If the mass is situated outside the spherical shell, the force can be calculated by integration from l = (r - R) to l= (r+ R), as shown here: l=r+R R - [ &F="TOmp: +(1+²²=² ) We SdF=fGmpat- de l=r-R What would the limits of integration be if the mass were situated inside the spherical shell? Include a labeled diagram to represent this situation.SEE MORE QUESTIONS