A beam ABC is pin-jointed at points A and B and is shown below. Calculate the maximum bending moment in kNm using anticlockwise moment as negative. Y X 3kN A 40kN 75 kN/m B C 0.5 m 0.25 m 0.25 m 0.75 m A 2M B 0.45 Steel brass 701 Torque supponed by steel TS = 0.7TT Total :. Tb = 0·35+ Torque OAC = 0 BC + OAB OAC = 0 · OBC = OAB Ts Ls GsJs " 077-(0.45) Tb Lb GbJb 75×10 6 x πTds² 0.4315 32 2 75X106X Tids² 32 0315 x 32 GS 75MPa Gb = 40MP : db = • 90mm ds = ? 0.37 + ( 2 ) T 40x106x 7d2b = 0-6 11 75x106x πds 2 10.08 32 40×106x πdb² 32 11 75 X 10.6 x πids 2 0-6x32 40 x 106 x 71 x0.092 19.2 400106 XA CO09) 10.08 x 40×106 XπT(0.09)² = 19.2 (75×106) x 77052 ds = 47.62mm X 65.47mm

A beam ABC is pin-jointed at points A and B and is shown below. Calculate the maximum bending moment in kNm using anticlockwise moment as negative. Y X 3kN A 40kN 75 kN/m B C 0.5 m 0.25 m 0.25 m 0.75 m A 2M B 0.45 Steel brass 701 Torque supponed by steel TS = 0.7TT Total :. Tb = 0·35+ Torque OAC = 0 BC + OAB OAC = 0 · OBC = OAB Ts Ls GsJs " 077-(0.45) Tb Lb GbJb 75×10 6 x πTds² 0.4315 32 2 75X106X Tids² 32 0315 x 32 GS 75MPa Gb = 40MP : db = • 90mm ds = ? 0.37 + ( 2 ) T 40x106x 7d2b = 0-6 11 75x106x πds 2 10.08 32 40×106x πdb² 32 11 75 X 10.6 x πids 2 0-6x32 40 x 106 x 71 x0.092 19.2 400106 XA CO09) 10.08 x 40×106 XπT(0.09)² = 19.2 (75×106) x 77052 ds = 47.62mm X 65.47mm

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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