A bullet of mass m is fired into a block of mass M that is at rest. The block, with the bullet embedded, slides distance d across a horizontal surface. The coefficient of kinetic friction is Find an expression for the bullet's speed Uballet- Express your answer in terms of the variables m, M, , d, and appropriate constants. ▸ View Available Hint(s) Ubullet = Submit Part B 195] ΑΣΦ Ubullet m+M X Incorrect; Try Again; 5 attempts remaining Submit m Previous Answers What is the speed of a 12 g bullet that, when fired into a 12 kg stationary wood block, causes the block to slide 5.6 cm across a wood table? Assume that μ = 0.20. Express your answer with the appropriate units. View Available Hint(s) μA Value Units ? ?

A bullet of mass m is fired into a block of mass M that is at rest. The block, with the bullet embedded, slides distance d across a horizontal surface. The coefficient of kinetic friction is Find an expression for the bullet's speed Uballet- Express your answer in terms of the variables m, M, , d, and appropriate constants. ▸ View Available Hint(s) Ubullet = Submit Part B 195] ΑΣΦ Ubullet m+M X Incorrect; Try Again; 5 attempts remaining Submit m Previous Answers What is the speed of a 12 g bullet that, when fired into a 12 kg stationary wood block, causes the block to slide 5.6 cm across a wood table? Assume that μ = 0.20. Express your answer with the appropriate units. View Available Hint(s) μA Value Units ? ?

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter9: Momentum And Its Conservation

Section9.1: Impulse And Momentum

Problem 1PP

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Maste session.masteringphysics.com/myct/itemView?assignmentProblemlD3D136303042&offset%3Dnext Apps (1) .. * YouTube to MP3 Co... phone cover for mo... Online Services Fo... AGARWAL-PHY-166 CHW6 Item 12 A 144-g baseball moving 28 m/s strikes a stationary 5.25-kg brick resting on small rollers so it moves without significant friction. After hitting the brick, the baseball bounces straight back, and the brick moves forward at 1.38 m/s. ACbefore value UNIIS Submit Request Answer Part C Determine the total kinetic energy after the collision. Express your answer to two significant figures and include the appropriate um НА KEafter = Value Units %3D Submit Request Answer Provide Feedback
p = mv J = Ft Ft = m Av Calculate the change in momentum of a 0.5 kg ball that strikes the floor at 15 m/s and bounces back up at 12 m/s. N
nloads/FINAL.pdf 3. A lead bullet of mass m = 10.0 g is travelling with a velocity of vo = 100 m/s when it strikes a wooden block. The block has a mass of M = 1.00 kg and is at rest on the table, as shown in the diagram below. The bullet embeds itself in the block and after the impact they slide together. %3D All the kinetic energy that is lost in the collision is converted into heat. Assume that all this heat goes into heating up the bullet. (a) What is the speed of the wooden block after the collision? (b) How much heat is generated as a result of the collision? (c) By how many degrees does the temperature of the bullet rise after the collision? (The specific heat of the bullet is 128 J/(kg °C).) (d) Suppose that the table has a coefficient of kinetic friction of u=0.2. At what distance will the block stop? M Vo m
Learning Goal: To understand the relationship between force, impulse, and momentum. The effect of a net force EF acting on an object is related both to the force and to the total time the force acts on the object. The physical quantity impulse J is a measure of both these effects. For a constant net force, the impulse is given by J = FAt. The impulse is a vector pointing in the same direction as the force vector. The units of J are N. sor kg · m/s. Recall that when a net force acts on an object, the object will accelerate, causing a change in its velocity. Hence the chiect's momentum in- mail will also change. The Figure F (N) L 12,000 0.0007 1 of 1 t (s) In Parts A, B, C consider the following situation. In a baseball game the batter swings and gets a good solid hit. His swing applies a force of 12,000 N to the ball for a time of 0.70 × 10-³ s. Part A Assuming that this force is constant, what is the magnitude J of the impulse on the ball? Enter your answer numerically in newton…
empt.php?attempt3D1499258&cmid%3D105924 Google O DAÜ Uzaktan Eğiti... Google äazi OInstagram A puck of mass m, = 5 kg collides with a puck of mass m, =5 kg. If the initial velocities of the pucks are V= 3 î 1i m m and V, = -2 i and the final velocities are V= -21 and Va= = 1.333 î m is the collision elastic or inelastic? Select one: Oa. inelastic Ob. elastic
The impulse of the force exerted by wooden target in stopping an arrow with a speed of 400m/s is -2kg-m/s. If it took 0.004 seconds for the arrow to penetrate the wooden block, what is the mass of the arrow? include figure and FBD.
The figure below shows two blocks with an initial velocity in opposite directions. The blocks collide. The mass of block 1 is 9.4 kg and the before collision velocity of block 1 is 6.9 m/s. The mass of block 2 is 2.2 kg and the before collision velocity of block 2 is -4.9 m/s. The after collision velocity of block 1 is 2.4241379310345 m/s. Determine the after collision velocity of block 2.
ab "ock esc Current Attempt in Progress Your answer is partially correct. A 0.00954-kg bullet is fired straight up at a falling wooden block that has a mass of 3.06 kg. The bullet has a speed of 538 m/s when it strikes the block. The block originally was dropped from rest from the top of a building and had been falling for a time t when the collision with the bullet occurs. As a result of the collision, the block (with the bullet in it) reverses direction, rises, and comes to a momentary halt at the top of the building. Find the time t. Number eTextbook and Media: Hint i 0.00854 Save for Later Q A P N @ NO 2 W S 43 X # H ntrol option command с Units E D 54 $ C R G Search or type URL F % * 10 5 V T MacBook Pro () > 6 G Assistance Used Attempts: 2 of 5 used Submit Answer Y B & 7 H U N 8 J O ( 9 M ✓ K 0 -0 O
A ezto.mheducation.com/ext/map/index.html?_con3con&external_browser3D0&launchUrl=https%253A%252F%252Fnewconnect.mheducation.com%252 D7 6 Saved Help 17 ! Required information A 0.100-kg ball collides elastically with a 0.300-kg ball that is at rest. The 0.100-kg ball was traveling in the positive x- direction at 8.30 m/s before the collision. t 2 of 2 nts What is the velocity of the 0.300-kg ball after the collision? If the velocity is in the -x-direction, enter a negative value. m/s eBook Hint Print eferences < Prev of 21 Next 17 aw %3D
A 1425 kg truck driving at 13.0 m/s collides elastically with a stationary 1175 kg car. If the car is traveling 14.25 m/s just after the collision, what is the velocity of the truck immediately after the collision? Assume that this is a perfectly elastic collision. Round your answer to the hundredths place. Final velocity of the truck = m/s
Activity 2. A 400N body starts up a 30° incline (µ = 0.2) with a velocity of 3m/s. How long must a 500N horizontal force act on the body to increase its velocity to 8m/s? How far will the body travel while the force is acting? (For the First Solution, apply the Resultant Impulse Equation) (For the Second Solution, apply the Impulse-Momentum Equation) | 400N 500N_
m1= 10 kg v1= 30 m/s ( North) m1= 20kg v2= 40 m/s ( 65 south of west) The collision is completely inelastic A. Find V'x B. Find V'y C. Represent V' graphically D. Find the magnitude |V'| E. Find the direction