A random sample of 300 high school students in a particular town showed that 165 smoke on a regular basis. Find the 95% confidence interval estimating the population percentage for smokers at this high school.

Q: Out of 300 people sampled, 156 had kids. Based on this construct a 90% confidence interval for the…

A: X = 156 N = 300

Q: The Diabetic Association of Pakistan sampled 4900 severely overweight Pakistanis between 20 and 59…

A: Given,sample size(n)=4900sample proportion(p^)=0.171-p^=1-0.17=0.83α=1-0.95=0.05α2=0.025Z0.025=1.96…

Q: In Cleveland, a random sample of 73 mail carriers showed that 10 had been bitten by an animal during…

A: Given, n1 = 73 x1 = 10 n2 = 80 x2 = 16 confidence level = 1 - α = 0.95 α = 0.05α2 = 0.025   To find,…

Q: Of 125 adults selected randomly from one town, 28 of them smoke. Construct a 99% confidence interval…

A: It is given that out of 125 adults in one town, 28 of them smoke. That is the value of n is 125 and…

Q: In Cleveland, a random sample of 74 mail carriers showed that 12 had been bitten by an animal during…

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Q: An online survey shows that 35% of CapU students consider taking in-person classes in Fall 2021.…

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Q: From a random sample of 64 high school seniors, the sample mean and standard deviation of the math…

A: Given,sample size(n)=64sample mean(x)=90standard deviation(s)=7degrees of…

Q: A simple random sample of 300 branches out of a total of 1200 branches of a UK travel agency found…

A: Given : Here population is total branches of a UK travel agency  Population Size (N) = 1200 Sample…

Q: A recent Gallop poll showed that 672 of 1019 adults nationwide think that marijuana should be…

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Q: A random sample of 1700 workers in a particular city found 646 workers who had full health insurance…

A: Given, The sample proportion is, Critical value: Using z-table, the z-critical value at the given…

Q: In a sample of 325 college seniors, 263 responded positively when asked if they have spring fever.…

A: Given data, n=325 x=263 sample proportion p=x/n= 263/325 =0.81 z-value at 95% confidence is Zc=1.96…

Q: Out of a sample of 150 people who walked into a fast food restaurant, 135 said they prefer ketchup…

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Q: A random sample of 250 preschool children in a local suburb revealed that only 232 had been…

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Q: From a random sample of 1000 Americans, it was discovered that 920 of them lived in neighborhoods…

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Q: A sample of 500 nursing applicants included 80 men.  Determine the 95% confidence interval for the…

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Q: Out of 600 people sampled, 312 had kids. Based on this, construct a 95% confidence interval for the…

A: In question,  Given that Out of 600 people sampled, 312 had kids. Then we'll construct the 95%…

Q: A sample of 35 different payroll departments found that employees worked an average of 240.6 days a…

A: Given that  Sample size (n) =35 Employed worked an average of 240.6 days a year x¯ = 240.6 days…

Q: A survey of 499 women for the American Orthopedic Foot and Ankle Society revealed that %37 wear…

A: Given : p = 0.37 q = 1 - p   = 1 - 0.37   = 0.63 n = 499

Q: A random sample of 110 Americans was asked how many hot dogs they eat each year.  The sample mean…

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Q: Out of 300 people sampled, 171 had kids. Based on this, construct a 95% confidence interval for the…

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Q: A recent survey showed that among 650 randomly selected subjects who completed 4 years of college,…

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Q: In a survery of 1118 American adults, 626 said they drink  coffee over tea. What would be the 95%…

A: It is given that, the number of American adults said that they drink coffee over tea is 626 out of…

Q: In a random sample of 1,250 adult drivers, 450 said they would cut their driving by 10 percent is…

A: From the provided information Sample size (n) = 1250 450 said they would cut their driving by 10…

Q: In a random sample of 500 people aged 20-24, 20% were smokers. In a random sample of 450 people aged…

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Q: A sample of 22 public high school students spent an average of 6.5 hours studying per week. Assuming…

A: Given: Sample Sizen=22Sample MeanX=6.5Standard Deviationσ=2.3 The z value corresponding to…

Q: Out of 100 people sampled, 44 have lied to a family member in the past month. Based on this,…

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Q: Out of 300 people sampled, 279 had kids. Based on this, construct a 90% confidence interval for the…

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Q: In a recent survey of 500 teenagers, 18.6% indicated that they had eaten junk food while watching TV…

A: Given Data: p^=0.186n=500

Q: In a random sample of 600 adults, 270 described themselves as vegetarians. Construct a 99%…

A: In a random sample of 600 adults, 270 described themselves as vegetarians.

Q: A random sample of 318 students from a large college were asked if they are planning to visit family…

A: Given 99% CI for population proportion of all students at this college is (0.78,0.98)

Q: In a survey participated by 100 college students, it was found out that 60% of them have personal…

A: We have to find confidence interval...

Q: An economist found that a random sample of 42 high school teachers had an average annual salary of…

A: We to create 99% confidence interval for the mean.

Q: A group of 40 bowlers showed that their average score was 192 with a standard deviation of 8. Find…

A: Given: n = 40 x¯ = 192 σ = 8 confidence level = 95%

Q: Out of 100 people sampled, 54 had kids. Based on this, construct a 90 % confidence interval for the…

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Q: In a random sample of 500 deer hunters it is found that 114 filled their tag (i.e. got a deer).…

A: INTRODUCTION :  CONFIDENCE INTERVAL FOR POPULATION PROPORTION           Let P be the proportion of…

Q: .A sample of seven college wrestlers had an average weight of 267 pounds with a sample standard…

A: It is given that sample mean is 267 and the sample standard deviation is 10.

Q: A survey conducted by the U.S. department of Labor found the 48 out of 500 heads of households were…

A: Given that, n = 500 x = 48 90% confidence interval

Q: A sample of 50 patients undergoing chemotherapy has a mean weight loss of 24 kg after they went the…

A: For the given data Find 99% confidence interval = ?

Q: A survey of 95 families showed that 40 of the families owned at least one tv. a. Find the 90%…

A: Number of families in a sample n =95 Let X be the number of families owned at least one tv = 40 p =…

Q: Of 130 adults selected randomly from one town, 30 of them smoke. Construct a 90% confidence interval…

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Q: A 95% confidence interval is constructed in order to estimate the proportion of adults who own an…

A:

Q: Based on a sample of 1000 adult Americans, USA Today reported that 840 of them preferred cheese on…

A: Given that on a sample of 1000 adult Americans, USA Today reported that 840 of them preferred…

Q: Out of 400 people sampled, 276 had kids. Based on this, construct a 90% confidence interval for the…

A: For 90% confidence intervalα=1-CI=1-0.90=0.10So, zα2=z0.102=z0.05=1.645

Q: A random sample of 328 medical doctors showed that 171 had a solo practice. Let p represent the…

A: Given, The best point estimate for p is,

Q: A sample of 50 patients undergoing chemotherapy has a mean weight loss of 24 kg after they went the…

A:

Q: In a random sample of 95 manufacturing firms, 67 indicated that their company attained ISO…

A: We have the sample size (n)=95The sample proportion is calculated by,p^=xn=Number of poeple…

Q: Out of 600 people sampled, 402 had kids. Based on this, construct a 95% confidence interval for the…

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Q: In a survey of 952 respondents, 620 of them voted in a recent election. Find a 95% confidence…

A: From the provided information, Number of respondents (n) = 952 Number of respondents who voted in a…

Q: A random sample of 75 college students of MSU is selected and 16 are found to have motorcycles on…

A: As per our guidelines we are suppose to answer only one question Givensample size(n)=75no.of…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.