Below is a conservation of energy problem. The solution to this problem is provided. Assess whether the solution provided is correct or incorrect AND EXPLAIN WHY. 4.6 kg block is at rest against a horizontal spring that is compressed by 0.40 m. The spring has a spring constant of k₁ = 2750 N/m. After leaving the spring, it travels up a 28° incline to a height of 2.8 m. At the top of the hill is a second spring with a spring constant of k₂ = 350 N/m. The horizontal portions are frictionless, but the hill has a coefficient of kinetic friction equal to uk= 0.16. The final velocity of the block is 9.78 m/s. How much is the second spring compressed by when the block comes to a stop against it? Simplifies to X₁ = 0.40 m h₁ = 0 m Vi = 0 m/s X = K₁ = 2750 N/m K₂= Wnc = 0 J 2 2 2 Wnc + mghi +½ kx₁² +½ mv² = mgh₁+½ kxf² +½ mvf2 Xf= = 350 N/m m = 4.6 kg 2 1/2 k₁x₁² = mghf + ¼ K₂Xf2 2750 N/m 350 N/m 2 ½ k₁ס² — mgħ –½ k₂xf² X (0.4 m)2 k 2 -X k₂ i f= 2gh 0.141 m X₁ = ? m hf = 2.8 m Vi = 0 m/s f 2(9.8 m/s2)(2.8 m) 2750 N/m

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter8: Conservation Of Energy
Section: Chapter Questions
Problem 24PQ: A block is placed on top of a vertical spring, and the spring compresses. Figure P8.24 depicts a...
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Below is a conservation of energy problem. The solution to this problem is provided. Assess
whether the solution provided is correct or incorrect AND EXPLAIN WHY.
=
4.6 kg block is at rest against a horizontal spring that is compressed by 0.40 m. The spring has
a spring constant of k₁ 2750 N/m. After leaving the spring, it travels up a 28° incline to a
height of 2.8 m. At the top of the hill is a second spring with a spring constant of k₂ = 350
N/m. The horizontal portions are frictionless, but the hill has a coefficient of kinetic friction
equal to uk = 0.16. The final velocity of the block is 9.78 m/s.
How much is the second spring compressed by when the block comes to a stop against
it?
Simplifies to
X₁ = 0.40 m
h₁ = 0 m
Vi = 0 m/s
xf
Wnc = 0 J
2
Wnc + mgh₁ +1/2 kx₁² +½ mv² = mgh₁+½ kxf² +½ mvf2
=
k₁ = 2750 N/m
k₂= 350 N/m
m = 4.6 kg
2
½ k₁x₁² = mghf + ½ K₂Xf2
2
½ k₁x;² — mghƒ _½ k₂xf²
Xf=
2750 N/m
350 N/m
(0.4 m)2
x
k 2 2gh
-X
f=
X₁ = ? m
h₁ = 2.8 m
Vi = 0 m/s
0.141 m
2(9.8 m/s2)(2.8 m)
2750 N/m
Transcribed Image Text:Below is a conservation of energy problem. The solution to this problem is provided. Assess whether the solution provided is correct or incorrect AND EXPLAIN WHY. = 4.6 kg block is at rest against a horizontal spring that is compressed by 0.40 m. The spring has a spring constant of k₁ 2750 N/m. After leaving the spring, it travels up a 28° incline to a height of 2.8 m. At the top of the hill is a second spring with a spring constant of k₂ = 350 N/m. The horizontal portions are frictionless, but the hill has a coefficient of kinetic friction equal to uk = 0.16. The final velocity of the block is 9.78 m/s. How much is the second spring compressed by when the block comes to a stop against it? Simplifies to X₁ = 0.40 m h₁ = 0 m Vi = 0 m/s xf Wnc = 0 J 2 Wnc + mgh₁ +1/2 kx₁² +½ mv² = mgh₁+½ kxf² +½ mvf2 = k₁ = 2750 N/m k₂= 350 N/m m = 4.6 kg 2 ½ k₁x₁² = mghf + ½ K₂Xf2 2 ½ k₁x;² — mghƒ _½ k₂xf² Xf= 2750 N/m 350 N/m (0.4 m)2 x k 2 2gh -X f= X₁ = ? m h₁ = 2.8 m Vi = 0 m/s 0.141 m 2(9.8 m/s2)(2.8 m) 2750 N/m
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