benzophenone (4°C). Given: Mass of benzophenone = 0.438g Molar mass of benzophenone = 182.217 g/mol Volume of cyclohexane = 25mL Density of cyclohexane = 0.779 g/mL
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- It has been observed experimentally that the AHpolution for methanol as solvent and dimethylsulfoxide (DMSO) as solute is negative. The structures of these compounds are given below. H. H A H3C "CH3 DMSO (dimethylsulfoxide) Methanol Please answer these questions in order to explain this fact: What IMFS are there between methanol molecules and other methanol molecules? Draw a diagram. What IMFS are there between DMSO molecules and other DMSO molecules? What IMFS are there between methanol molecules and DMSO molecules? Draw a diagram. If AHsolution for dissolving DMSO in methanol is negative, what does this say about the energy released in mixing methanol and DMSO molecules (AHmixing) as compared to the energy required in separating solute molecules from each other (AHsolute) and separating solvent molecules from each other (AHsolvent)? 26Henry's constant for the solubility of ethylene gas in H2O at 20 degrees C is 10.1 x 10-5 atm-1 Calculate the mass of ethylene gas that wceill dissolve in 1000 g of H2O under an ethylene- pressure of 2 atm at 20 degrees C. Given: Methylene = 28 g mol-1 and M(H2O) = 18 g mol-1Explaining Vapor Pressure in Terms of IMFs Given the shown structural formulas for these four compounds, explain their relative vapor pressures in terms of types and extents of IMFs: OH I H₂C-CH₂ ethanol HO OH | | H₂C-CH₂ ethylene glycol Solution CH₂CH₂OH: H-bonding & LDF. CH₂OHCH₂OH: Stronger H-bonding than ethanol (also LDF), and higher MM than H₂O. More viscous than ethanol, thus quite a low P vap. CH3-CH₂-0-CH₂ CH3 and H-O-H diethyl ether water C4H₁0O: Dispersion forces AND dipole-dipole. Diethylether is quite a volatile substance, with quite a high Pvap: vap• H₂O: H-bonding & LDF. Although the molecule with the LOWEST Molar Mass, it has Of the choices above, ONLY ethylene glycol has a LOWER Pvap- a low Pvap. LOWEST Pvap HIGHEST PvapWhen 127. mg of a certain molecular compound X are dissolved in 55.0 g of dibenzyl ether point of the solution is measured to be 1.6 °C. Calculate the molar mass of X. If you need any additional information on dibenzyl ether, use only what you find in the ALEKS Data resource. Also, be sure your answer has a unit symbol, and is rounded to the correct number of significant digits. ((C6H₂CH₂)₂0), 2 the freezing OO B olo XuTable 1. Experimentally Determined Changes in Freezing Point for Aqueous Solutions Substance Freezing Point Tr (°C) AT = T°r-T Trial 1 -0.1°C Pure Water Pure Water Trial 2 T=-04°C Average Tr= -1-5 °C NaCI/Water Solution Ethylene Glycol/Water Solution Tr= 0.2 °C -3:2°C - 3 T2 Tr- A°C -49°C - 6 TS Methanol/Water Solution (Amoles (6.02X10 Table 2. Three Ratios for Specifying the Composition of Aqueous Solutions gsolute/gsolvent mole,olutegsolvent moleparticles/gsolvent Substance 5.029/5M •085q /sg 59 5-121 102 NaCI/Water Solution 5.05X10" L 5g . 0147 na 0.85X16) 5g .0434 /59 523/5m 5M Ethylene Glycol/Water Solution Methanol/Water Solution 1. Might any of the ratios you calculated for Table 2 above be useful for predicting how the freezing point of a solution would differ from that of the pure liquid? Explain.1-Pentanol to 1-bromopentane Chemicals: - 60ml Conc. Sulfuric Acid - 100ml Saturated Sodium bicarbonate - 65ml 1-Pentanol - 78g sodium bromide - Distilled water - 58.42g 1-Bromopentane 1-Pentanol Sodium Bromide Sulfuric Acid 1-Bromopentane Formula C5H12O NaBr H2SO4 C5H11Br MW (g/mol) 88.15 102.894 98.078 151.04 Density (g/mL) 0.811 3.21 1.84 1.218 Boiling point (*C) 138 1,396 337 130 NaBr(aq) + H2SO4(aq) -> NaHSO4(aq) + HBr(aq) CH3(CH2)4OH(aq) + H+ Br- (aq) CH3(CH2)4OH2 (aq) + Br-(aq) CH3(CH2)4OH2 (aq) + Br-(aq) CH3(CH2)4Br(aq) + H2O(aq) How do I calculate the percent yield and identify the limiting reagent?Consider the solution process below. Select the true statement. AH1 AH, AH Expanded solvent Expanded solute Solute Solvent Step 1 Step 2 AH3 Direct formation of solution Step 3 AH3 is endothermic. O Enthalpy of solutions, AHsolution = AH1 + AH2 + AH3 %3D The greater the intermolecular force between solute molecules, the more exothermic AH, is. O AHsolution is always positive.= 209; S =32 ). What is the solubility of Bi2S3 in g/L (At. Mass: Bi = Ksp Bi2S3= 1.6 x 10-72 Answer format: 1.00x10-14 (Don't put the unit. Round-off your final answer in two decimal place)need this answer with explanation Considera mixture prepared by adding 0.1 moles of benzoic acid,and 1.5 moles of diethyl etherWhich of the following statements is false concerning the resulting mixture? A. The solution exhibits positive deviations from Raoult's law B. ∆H for the solution should be endothermic C. The intermolecular forces are stronger in solution than in either pure diethyl ether or pure benzoic acid. D. Molecules in the solution have a higher tendency to escape. E The solution with x =0.5 will have a lower boiling point than either pure diethyl ether or pure benzoic acid. need explanation for all Statementsutions - Homework - 2022.pdf - Adobe Acrobat Pro DC (32-bit) E-Sign Window Help ols Chapter 14 - Soluti. x 2 / 3 135% 8) Determine the freezing point of a solution that contains 63.8 g of naphthalene (C10H8, molar mass = 128.16 g/mol) dissolved in 275. mL of benzene (d = 0.877 g/mL). Pure benzene has a melting point of 5.50°C and a freezing point depression constant of 4.90°C/m. d fliv ebruogrnos sniwollot srb lo rdairlW (1 (EelD) onimaly tomit (I acorous (CH3COCH?) stuloe slitslovn qps adnoone B) O 300 CISO Inioq anilam omce ori overl ls verdT (3 D)0 100 a VICI oqmot eirs s ) vilidulce ort oninnsis (E 0.26 gnivlozaib yd bonisido pexsue Ce ylienob e 26rd noituloe adt it DH arlo inalom srb noituloe 1 MS.0lo (J) omulov torWCyclohexanol 10 ml Mass of cyclohexanol 9.62 g – 0.053 mol Theroretical yield cyclohexene–7.89g - ? mol Therotical mass of cyclohexene- Actual yield- 6.8ml –4.055 g –? mol Percent yield- 51.04% Boiling point of cyclohexene -83 degree Celsius Theroretical boling point -83 degree Celsius can i get some clarification plsCalculate the kf of cyclo hexane using the freezing point of ayclohexane 650i and benzophe none 4°C solution. gof benzopheno ne = 0.438 9 MM uf benzophe none = 182.217 glmol volume uf ay clohexane = 25 mL Density of g/ml %3D %3D 4 ayclohey ane = 0.79SEE MORE QUESTIONS