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A: Since we only answer up to three sub-parts, we'll answer the first three. Please resubmit the…
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Q: which one has the most red-shifted C-O NH (a) F (b) D K G. H. (d) (c)
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Q: D. CHBr-CBr-CH,
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Q: .CO2H
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Q: NH N.
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Rank the following bonds in order of increasing stretching frequency (cm-1) in IR
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- PbBr2 Ksp = 6.3 × 10-6100 MS-NU-3528 80 40 Huuluwfyulwluylpwlwwlw 110 10 20 30 40 50 60 70 80 90 100 120 m/z Relative Intensity 20If the peak width w of both Peak 1 and Peak 2 fro eon 1g is 0.5 minutes, what is the resolution factor between the two peaks? 1.13 Selectivity is Peak 1 (6.0 min, Peak 2 w=0.5 (6.8 min, w=0.5 25 min) min) 20 15 Hold up peak (1.8 min) 10 0. 0. 4. 8. time (minutes) 2. 5. Signal
- Background 1234|5| C12H22O11 + O₂ CO₂ + H₂O Mg(OH)2 + H₂SO4 MgSO4 + H₂O NaOH + CuSO4 -Na2SO4 + Cu(OH)2 CH2 + Oz = H2O + CO2 Fe + 0₂ Fe₂O3 Mg3(PO4)2 + H₂ Mg + H3PO4 NH4NO3-N₂O + H₂O Cl₂ + KBr KCI + Br₂ ck to add speaker notes % 5 A 6 D 7 Ö * 8 ( 16 17 | )Calibration curve and propagation of uncertainty for exponents. The following data were obtained when a Ca2+ 14-38.3. 11 100 TRANSMETTANCE D C8H9CIO 4000 10 HSP-01-151 9 3000 8 2:2 7 2000 6 : 5 ppm 2 NAVENUMBERal 4 3 1500 : Vala 2 1000 3 1 0 500 200 180 COS-04-715 DEPT-90 DEPT-135 160 140 120 بلد لد 100 ppm 80 60 40 20 0
- How can the selectivity factor be manipulated in (a) GC and (b) LC?Mass spectrometry is an extremely versatile detection system for GC. However, interfacing an HPLC system to a mass spectrometer is a much more difficult task. Describe the major reasons why it is more difficult to combine HPLC with mass spectrometry than it is to combine GC with mass spectrometry.Intensity (a.u.) 4000 3352 cm¹ 3500 3000 UNKNOWN B 1710 cm¹ 2000 1668 cm¹ 2500 Wavenumber (cm¹¹) 1500 1101 cm 1000 500
- What is the resolution in ppm NO3-N of a spectrophotometer that gives a reading of 0.600 absorbance units for 25 ppm NO3-N? The resolution of the instrument is 0.001 absorbance units.3. Fill in the following for the correspondence between % transmittance and absorbance: 100.0 % T = 0.0 absorbance 1.00 absorbance = (0.0 % T 25.0 % T = absorbance 0.25 absorbance = % TPls make sure it's 10000% correct and explain pls and thank you