Diagram shows a loop traverse, along with the raw, or unadjusted, field data oop Traverse 64° 21'15" 677.97 D 616.05 107°33'45* 206° 35'15" Field data unadjusted 971.26 $ 81° 42'15"E (assumed) 690.88 96°38'45" 783.32 12 13 1. What should be the sum of the interior angles of this polygon? 720 degrees 360 degrees 540 degrees 270 degrees 15 What is the actual unadjusted sum of the field angles? 270° 0' 30" 540° 02' 30" 360° 0' 30" 540° 0' 30"

Diagram shows a loop traverse, along with the raw, or unadjusted, field data oop Traverse 64° 21'15" 677.97 D 616.05 107°33'45* 206° 35'15" Field data unadjusted 971.26 $ 81° 42'15"E (assumed) 690.88 96°38'45" 783.32 12 13 1. What should be the sum of the interior angles of this polygon? 720 degrees 360 degrees 540 degrees 270 degrees 15 What is the actual unadjusted sum of the field angles? 270° 0' 30" 540° 02' 30" 360° 0' 30" 540° 0' 30"

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

SURVEYING A closed traverse has a following data: LINES DISTANCE BEARING AB 24 m S 16° W BC 16 S 69° E CD ? N 58° E DA ? S 81° W Calculate length of line AD.
Given the close traverse survey below, compute for all the adjusted Lengths and Bearings. Show complete solution. PS. Answer to this problem requires a file upload, be sure to upload it here together with your solutions. TY. 58°34 364.55 1. Length () 347.00 364.55 472.74 292.94 Line Azimuth 509 05 38 258 34 22 128 04 44 60 21 26 ST TU •00 UV SHOT ON MI 10T I BY: ALEXIS VS
2. Correct the survey data below for a closed traverse. LINE OBSERVED DIMENSIONS DISTANCE BEARING (m) АВ 319.27 N 86°46' E N 1°35' W S 78°50' ВС 551.35 CD 417.26 W DE 220.87 S 30°25' W EA 375.36 S 36°17' E
Convert the following distances given in survey feet to meters:(a) 537.52 sft (b) 504,864.39 sft (c) 3874.26 sft
3. The following tabulated data is to be used in determining the area of traverse ABCDE by the DMD method. Determine the total area of the traverse in m?. Adjusted Latitude Adjusted Departure Course +N -S +E -W АВ 558.25 78.34 ВС 102.58 746.38 CD 285.33 319.24 DE 352.05 395.68 EA 23.45 591.60 Sums +660.83 m -660.83 m +1065.62 m -1065.62
Use DMD & DPD Method to calculate the Area of the closed traverse whose data is given below. Draw the figure. LINE CORRECTED DEPARTURE CORRECTED DISTANCE 413.53341 596.41168 AB CORRECTED LATITUDE +296.42872 - 246.85339 + 104.50281 154.07815 + 288.33990 BC CD +542.92753 - 597.93576 - 233.33167 606.99919 DA 279.61356
3. Complete the table and sketch the traverse, assuming no measurements were obtained for line EF. LATITUDE DEPARTURE LINE LENGTH, m BEARING N (+) S() E(+) W(-) АВ N 5°30'8.33" E 490.71 47.27 BC 587.12 608.89 CD 327.41 786.78 DE 1002.76 218.32 EF FA 375.01 544.64 SUM
Bearing Angle Traverse Given the tabulated measurement of the closed traverse as shown. Determine the missing data. Line Length Bearing AB 413.600 m N 09°30’ W BC 304.380 m N 55°06’ W CD 407.210 m S 57°35’ W DE Unknown S 04°05’ E EA 649.630 m Unknown Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.
Calculate the omitted lengths of the lines of BC and CD of a closed traverse ABCDEA, using the following data: Line Length Bearing ΔΕ AN AB 104.85 14°31 +26.29 +101.50 BC ? 319°42' CD ? 347°15' DE 91.44 5°16′ EA 596.80 168°12' +122.05-584.21 - - - +8.39 +91.06
SURVEYING From the following traverse: (Use 3 decimal point) LINE DISTANCE BEARING AB 370m N 15° E BC 648 S 86° E CD 470 S 19° W DA 585 N 78° W Calculate the area of the traverse by DPD method.
Solve for the missing measurements (Bearings of line BC and DE) given the data for a closed traverse. Line Length Bearing AB 529.6 N 48° 20' E BC 592 ? CD 563.6 S 7° 59' E DE 753.4 ? EA 428.2 N 48° 12' W
A closed traverse has the following data: What is the value of X + Y + Z? Line Latitude Departure DMD 2A AB 30.68 1,459.28 BC 79.52 Y 2,847.24 CD |139.29 DA |-5.92 N