Compute the EQUIVALENT RESISTANCE of the circuit shown below. Then find the voltage drop across each resistor, the current through each resistor, & the current put out by the battery (l。). (R₁ = 7 £2, R₂ = 3, R3 = 52, R4 = 8, and V₁ = 29 V.) Vo Req = 2.083 ΧΩ Io = 5.81 A R3 R2 R1 M M R4 × I₁ = 1.73 A 12 1,86 A 13 = 1.86 A V₁ = 12.14 V × = = V₂ 5.57 V × V3= 9.29 V = = 14 = V4 0.36 A 2.86 V × =

sq 4. Maximum surface resistance. Consider a square sheet of side L, thickness d, and electrical resistivity p. The resistance measured between opposite edges of the sheet is called the surface resistance: R = pL/ Ld = p/d, which is independent of the area of the sheet. (R is called the resistance per square and is expected in ohms per square, because p/d has the dimensions of ohms.) If we express p by p=m/ne²t, then Rq=m/ndet. Suppose now that the minimum value of the collision time is determined by scattering from surfaces of the sheet, so that Td/v, where v is the Fermi velocity. Thus the maximum surface resistivity is Rmvp/nd²e². Show for a monatomic metal sheet one atom thickness that sq Rħ/e² = 4.1k, where lkn is 10³ ohms. sq

The relation between resistance R and temperature T for a thermistor (a device that measures temperature) closely follows    R = Ro e[Beta (1/T  - 1/To)]   where R is the resistance in ohms measured at temperature K, and Beta is a material constant.  What are the units of Beta and Ro?  Clearly show  how you decided on your answer.

Conduc-Thor-s. Thor has two square prism conductors that are made of the same ohmic material and with properties indicated below. Conductor Length | Cross-Section Side Length Alpha L Beta L/2 s/4 Suppose both conductors are subject to the same potential difference AV across their length while keeping their temperatures fixed. Which of the following is the correct relation between the electric currents, Ia and IB, through Alpha and Beta? O A. Ia = 8IB O B. 8Ia = Ig O. Ia = 4I8 O D. 4Ig = Ig Clear my choice