Question 1A horizontal beam AB with cross-sectional dimensions (b= 0.75 in.) x (h= 8.0 in.) is supported by an inclinedstrut CD and carries a load P= 2,700 lb at joint B. The strut, which consists of two bars each of thickness 5b/8,is connected to the beam by a bolt passing through the three bars meeting at joint C.(a) If the allowable shear stress in the bolt is 13,000 psi, what is the minimum required diameter of the bolt atC?(b) If the allowable bearing stress in the bolt is 19,000 psi, what is the minimum required diameter of the boltat C?b-5 ftBeam AB (b x h)OBhBolt (dmin)3 ftPh25bDStrut CD

Answered: Image /qna-images/answer/39c830a3-569c-44c1-b1fc-7e05170f50c6.jpg

d carries a load P= 2,700 lb at joint B. The strut, which consists of two bars d to the beam by a bolt passing through the three bars meeting at joint C. owable shear stress in the bolt is 13,000 psi, what is the minimum require lowable bearing stress in the bolt is 19,000 psi, what is the minimum requi

d carries a load P= 2,700 lb at joint B. The strut, which consists of two bars d to the beam by a bolt passing through the three bars meeting at joint C. owable shear stress in the bolt is 13,000 psi, what is the minimum require lowable bearing stress in the bolt is 19,000 psi, what is the minimum requi

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

b) This is a concrete frame (the interior lines represent reinforcing bars), If P is dead load, draw the BMD and the SFD as a result of ULTIMATE LOAD. 6.0 ft. P= 1.0 Kip Own weight of the beam = 1.0 kip/ft. (Uniform dead load)
Problem # 3: The strut AB made from two bars (thickness of each bar = 0.50 in) is connected to a rectangular beam CD (b=0.80 in x h = 7.5 in) at joint B. The beam carries a concentrated load of 2750 lb at the end joint D. (a) determine the minimum diameter of the bolt at B if the shearing stress in the bolt is not to exceed 14000 psi. (b) determine the minimum diameter of the bolt at B if the allowable bearing stress in the bar plate is 20000 psi. Detail of joint B 0.80 in 3 ft с VO A 5 ft- + B 6 ft- D 2750 lb 3.75 in 3.75 in Strut AB - Beam CD (b X h) Bolt (dmin) -0.50 in
The center panel of the truss contains two flexible cables. What load P will cause a compressive force of 2000 N in BD? Then determine which tension diagonal BE or CD is acting and the force in it. B D R₁ L L L CLEL P R₂
Determine the force in member AB of the truss below. Indicate as positive if the member is in tension and negative (-) if the member is in compression. Provide the answer in kips t H 1.5 k F 2 k 2 k G B C . 8 ft 8 ft -8 ft 8 ft E D 4 ft Q Search securySearch 5 17 & 8
D E b G H a a a + a a a P1 P2 P3 Determine the force in members FE, LE, and KL of the truss, and state if the members are in tension or compression. Type your answer as the force using three significant digits, followed by the unit and then a Tor C to indication tension of compression. P - 4 kN, P2- 5 kN, P3- 12 kN, P4 = 6 kN a- 2 m and b-3 m What is the force in FE? What is the force in LE? What is the force in KL?
Given the truss and loading shown below, determine the stress at member DF if Pµ = 18.375 Kips and its area is 16 in². Assume that the truss are simply supported at joint M and E. Express your answer in ksi. Use three decimal places. RM Pu Pu 0 Pu Pu 8 @ 10' = 80' Pu B Pu CF Pu et LK J I H G F 8@10' 80' RE
2: The truss is supported by a pin in point A and a roller at point E. Show your FBD 2 m F 5 kN. B 3 m A E 10 kN 5 m 5 m
Channel sections are used as a purlin. The top chords of the truss are sloped at 5H to 2V. Trusses are spaced 5m on centers and the purlins are spaced 1.4m on centers. Use the properties of the channel section BELOW. Loads: (Consider all loads pass thru the centroid of the section.) Dead load = 750 Pa Live load = 1,000 Pa Wind load = 1,400Pa Wind coefficients: Windward = 0.3 Leeward = -0.5 Use Fbx=Fby=250 MPa. Determine the maximum value of the interaction equation using the load combination of 0.75(D+L+W)
Part 2 A Pratt roof truss is loaded as shown. Using the method of joints and the method of sections, determine the force in all members. the force P.325KN 80 kN P kN 60 kN D H 8 m 60 kN A G---Y. MATHaling.com 6 m 6 m E 6 m 40 kN 100 kN 6 m
SITUATION 1 Determine (approximately) the force in each member of the truss. Assume the diagonals can support either a tensile or a compressíve force and assuming that the díagonals cannot support a compressíve force. A. Use Method 2 7 k 14 k 14 k 7 k Н F E oo 2 k 380 6 ft A D В C 8 ft 8 ft 8 ft B. Use Method 1 50 kN 40 kN 20 kN E D 3 m B 3 m 3 m
Channel sections are used as a purlin. The top chords of the truss are sloped at 5H to 2V. Trusses are spaced 5m on centers and the purlins are spaced 1.4m on centers. Use the properties of the channel section given below. Loads: (Consider all loads pass thru the centroid of the section.) Dead load = 750 Pa Live load = 1,000 Pa Wind load = 1,400Pa Wind coefficients: Windward = 0.3 Leeward = -0.5 Use Fbx=Fby=250 MPa. Determine the maximum value of the interaction equation using the load combination of 0.75(D+L+W)
2 A simply supported beam has a dimension of 300mmw x 600mmh has a span of 6m. it has a superimposed load of 30KN/m and live load of 50KN. It has a specified concrete strength of 28MPa and yield strength of 420MPa. Distance of centroid steel area to outermost fiber is 60mm. a. What is the maximum moment of the beam? b. What is the required tension steel area? Use et = 0.004