Draw the equivalent circuit of a DC Motor, Separated Excited DC Motor and Compounded DC Motor. Label each component properly Q3 (a)
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- The following figure shows a simplified endivi and inductor for a dc motor. The inductor has an average magnetic path length of 50 cm and a cross-sectional area of 12 cm2. The mean path length of the endivi is 5 cm and the cross-sectional area is given as 12 cm2. The air gap between the armature and the inductor is 0.05 cm, and the cross-sectional area of each air gap (including fringe effect) is 14 cm2. The magnetic permeability of the iron of the core is µr =2000 H/m and 200 turns are wound on the core. If the current through the conductor is set to be 1 A,a) What is the mmm force of the magnetic circuit?b) What is the reluctance of the inductor and armature?c) What is the magnetic flux density in the air gap?Is it Tesla?d) Calculate the inductance of the winding.e) If 10 turns of bandage are wrapped around the armature under these conditions,What is the torque to be induced if current A is passed?Q9 / What are the function of brushes , pole and commutator in DC machineA DC, separately excited motor is used to drive a constant-torque load. The field circuit is excited by a full-wave, AC/DC SCR converter. The armature circuit of the motor is connected to a constant dc voltage source of 160 V. The inductance of the field circuit is large, and the field current is continuous. The field AC voltage (input to the converter) is 147 V (rms), and the field resistance is 100 N. The armature resistance is 1.2 N. When the triggering angle of the SCRS is adjusted to zero, the motor speed is 1000 rpm, and the armature current is 10 A. Calculate the average current and dc power of the field i. A1 F1 circuit when the triggering angle is equal to 15°. La Ra If A a P; W M • If the motor speed is to be increased to 1400 rpm, what is the F2 A2 triggering angle? (a) Circuit a =
- Q4/B/ What are the principal characteristics of a series DC motor? What are its uses? Core Mc• Q5/ in a DC motor. List and describe the types of losses that occurA DC, separately excited motor is used to drive a constant-torque load. The field circuit is excited by a full-wave, AC/DC SCR converter. The armature circuit of the motor is connected to a constant dc voltage source of 160 V. The inductance of the field circuit is large, and the field current is continuous. The field AC voltage (input to the converter) is 127 V (rms), and the field resistance is 110 N. The armature resistance is 2.2 N. When the triggering angle of the SCRS is adjusted to zero, the motor speed is 1300 rpm, and the armature current is 13 A. A1 • Calculate the average current and dc power of the field circuit when the triggering angle is equal to 15°. La Ra If 1.04 A Va M P¡ = 110.89 W A2 If the motor speed is to be increased to 1700 rpm, what is the triggering angle? (a) Circuit a =
- Speed control of a 140 V, 1.68 kW DC motor single phase thyristor full wave AC-DC It is made by the converter. AA supply voltage 220 V (rms) Is 50. In the converter It is assumed that there is no loss. The armature resistance of the DC motor is = 0.417 Q. Very a large inductance is connected in series with the motor. The motor voltage constant is = 0.0964 V/rpm. The motor can be considered as a permanent magnet DC. According to this, a) Draw the driver (converter-motor) power circuit. b) Calculate the nominal current of the motor. c) Supply voltage, supply current, converter output voltage for ignition angle a = 30 ° and Draw the waveforms for the converter output current. d) = 950 rpm and for nominal current, d1) The firing angle of the converter, d2) Effective value of supply and thyristor current, d3) Supply power factor, calculate.The excitation circuit of a free-excited DC motor is a single-phase full- wave uncontrolled rectifier and The armature circuit is fed with a single-phase full-wave controlled rectifier. both rectifiers for AC voltage voltage 220 V(rms) ,is 50 Hz. Excitation O resistance of motor Rf = 100, armature force resistance Ra = 2 0 and motor voltage constant Kv = 0.25 V/(A - r/s). The motor is a fixed 10Nm buy under load a) Draw the driver (converter-motor) power circuit. To rotate with 1200 d/d of the motor, b) Calculate the thyristor assembly. c) When the engine is heavily loaded, with a suitable probability value for supply voltage, armature voltage, armature flow wavelengths draw below. d) Calculate the motor power (total input power). (Note: Va = IaRa + ea, Vf = IfRf, ea = Kv Ifw and Te = Kv Ifla)Write a MATLAB program describing the following figure. one cycle TIME PRESSURE amplitude
- Self-Lift P/O Luo- Dc-dc Converter i need explain Drive for seperately excited dc motorThe armature circuit of a free excited direct current motor with a nominal voltage of 600 V is fed from an adjusted direct voltage source. The excitation circuit is also powered from a regulated voltage source. It is used in an application that requires motor speed adjustment. The speed of the motor at the nominal armature voltage was measured as 1600 rpm. All losses of the motor and voltage source and the effect of armature reaction are neglected. It is accepted that the engine is not saturated.Answer the questions below.a) Draw the armature and excitation circuit of the motor and write the formulas for the equivalent circuit.b) If the load moment of the motor at the nominal armature voltage is 420 Nm, then calculate the armature current and the input power of the motor.c) If the armature voltage of the motor is kept constant at 600 V and the excitation current is decreased until the speed reaches 4000 rpm, then calculate the shaft moment. Show this working area on the M = f (W) axis.Design a LabVIEW program that sweep Servo motor from 0 degrees to the specified angle and repeat Design a LabVIEW program to demonstrate a 28BYJ-48 stepper motor operating in both directions: 5 seconds anticlockwise and 5 seconds clockwise