Evib = @. + @.ye v+• +... %3D Molecule u (amu) k (Nm-') we(cm-1) Wxe (cm-1) wYe (cm¬1) 'H 1271 1.00 310 2309.60 39.36 -0.09 2H 1°F 1.82 960 2998.19 45.76 12C 160 6.86 1900 2169.82 13.29 0.01 14N !ªN 7.00 2290 2358.07 14.19 -0.01 14N 160+ 7.47 2490 2377.48 16.45 14N 160 7.47 1600 1904.41 14.19 0.02 14N 160- 7.47 830 1372 160 l60 8.00 1180 1580.36 12.07 0.05 19F 1ºF 9.50 440 891.2 35C1 5CI 17.48 320 560.50 2.90 0.02

Chemistry for Engineering Students
3rd Edition
ISBN:9781285199023
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter5: Gases
Section: Chapter Questions
Problem 5.23PAE
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Calculate the vibrational energy of the v = 2 state of 1H127 I relative to the ground state, including the anharmonic corrections.

Evib = @.
+ @.ye v+•
+...
%3D
Molecule
u (amu) k (Nm-') we(cm-1) Wxe (cm-1) wYe (cm¬1)
'H 1271
1.00
310
2309.60
39.36
-0.09
2H 1°F
1.82
960
2998.19
45.76
12C 160
6.86
1900
2169.82
13.29
0.01
14N !ªN
7.00
2290
2358.07
14.19
-0.01
14N 160+
7.47
2490
2377.48
16.45
14N 160
7.47
1600
1904.41
14.19
0.02
14N 160-
7.47
830
1372
160 l60
8.00
1180
1580.36
12.07
0.05
19F 1ºF
9.50
440
891.2
35C1 5CI
17.48
320
560.50
2.90
0.02
Transcribed Image Text:Evib = @. + @.ye v+• +... %3D Molecule u (amu) k (Nm-') we(cm-1) Wxe (cm-1) wYe (cm¬1) 'H 1271 1.00 310 2309.60 39.36 -0.09 2H 1°F 1.82 960 2998.19 45.76 12C 160 6.86 1900 2169.82 13.29 0.01 14N !ªN 7.00 2290 2358.07 14.19 -0.01 14N 160+ 7.47 2490 2377.48 16.45 14N 160 7.47 1600 1904.41 14.19 0.02 14N 160- 7.47 830 1372 160 l60 8.00 1180 1580.36 12.07 0.05 19F 1ºF 9.50 440 891.2 35C1 5CI 17.48 320 560.50 2.90 0.02
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