Find the areas of the surfaces generated by revolving the curves about the indicated axes. If you have a grapher, youmay want to graph these curves to see what they look like. x = (1/3)y3/2 - y1/2, 1 ≤ y ≤ 3; y-axis

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 44E
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Find the areas of the surfaces generated by revolving the curves about the indicated axes. If you have a grapher, you
may want to graph these curves to see what they look like. x = (1/3)y3/2 - y1/2, 1 ≤ y ≤ 3; y-axis

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Step 1

The given curve is: x=13y32-y121y3.

We have to find the surface area generated by the given curve when revolved about the y-axis.

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