GCT GAC ATC CTC CTC mutated DNA sequence mutated mRNA sequence mutated amino acid sequence Above is the mutated DNA sequence for part of the 21 hydroxykase gene. Provide the mutated mRNA and amino acid sequence.
Q: al mRNA: 5’- AUG GGC UCG ACC UUG -3’ Mutant mRNA 1: 5’- AUG GGC UAG ACC UUG -3’ Mutant mRNA 2: 5’-…
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Q: CTA GCC CTC CGT TAC TAG TTA CCT ACT TAT TCA ATT TTG TAA ACG CTC ATC CGA ACC CGC TTT TAA TTG CCC ACT…
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Q: CTA GCC CTC CGT TAC TAG TTA CCT ACT TAT TCA ATT TTG TAA ACG CTC ATC CGA ACC CGC TTT TAA TTG CCC ACT…
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Gene Interactions
When the expression of a single trait is influenced by two or more different non-allelic genes, it is termed as genetic interaction. According to Mendel's law of inheritance, each gene functions in its own way and does not depend on the function of another gene, i.e., a single gene controls each of seven characteristics considered, but the complex contribution of many different genes determine many traits of an organism.
Gene Expression
Gene expression is a process by which the instructions present in deoxyribonucleic acid (DNA) are converted into useful molecules such as proteins, and functional messenger ribonucleic (mRNA) molecules in the case of non-protein-coding genes.
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mutated amino acid sequence |
Above is the mutated DNA sequence for part of the 21 hydroxykase gene. Provide the mutated mRNA and amino acid sequence.
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- 3’ – ACCTCTTACTTTTATATATAGGGAAGACTAATTGTC – 5’ Transcribe the template strand be sure to use the 5’ and 3’ directions appropriately on the mRNA, feel free to rewrite the DNA strand if needed to make it easier to interpret. Make sure to label the mRNA with a "5'cap" and place 10 A's to form the poly-A tail.mRNA sequence of A gene If we have the following mutations, find the type of the mutation (silent or missense or nonsense?) 17CàU 36GàA 49GàU 115AàC 5’ AAACUGUGACUGAACCUCAAACCCCAAACCAGCCCGAGGAGAACCACAUUCUCCCAGGGA CCCAGGGCGGGCCGUGACCCCUGCGGCGGAGAAGCCUUGGAUAUUUCCACUUCAGAAGCC UACUGGGGAAGGCUGAGGGGUCCCAGCUCCCCACGCUGGCUGCUGUGCAGAUGCUGGACG ACAGAGCCAGGAGGGAGGCCGCCAAGAAGGAGAAGGUAGAGCAGAUCCUGGCAGAGUUCCAGC UGCAGGAGGAGGACCUGAAGAAGGUGAUGAGACGGAUGCAGAAGGAGAUGGACCGCGGCCUGA GGUAGAAGCCGCUGGGGCUUGGGGCU-3’Sequence: CCACCTGTACCCGGACACACCCTGGTGTCC 1. Identify the gene from which the querysequence originates (Name of gene) 2. Provide the FULLprotein sequence encoded by the gene. 3. Are different splice variants known for this gene? 4. What human disease has been connected to this gene? 5. Calculate molecular weight (kiloDalton, kD) and calculated pI (the pH where the protein carries no net electrical charge) of the protein.
- Given the following DNA sequence: 3'-TACTTNGTNCTNTCN-5' where N stands for any nucleotide, give the complementary mRNA sequence. Indicate direction of strand as 3'--> 5' or 5'--> 3' as in the given sequence above. Give the amino acid sequence of your mRNA sequencelin No. 1. Indicate direction of strand as above. Use all lowercase letters, 3-letter name of amino acid separated by a hyphen (-), no spaces in-between.Write the sequence of the mRNA molecule synthesized from a DNA template strand having the sequence 5'-ATTACAGGCGGT-3' 5'- UAAUGUCCGCCA Incorrect Write the amino acid sequence encoded by the mRNA base sequence 5'-GAGUUAGUUUGUAAGUGC-3' Assume the reading frame starts at the 5' end. Refer to the codon table . Amino acid sequence: Glu-Leu-Val-Cys-Lys-Cys What is the sequence of the polypeptide formed on addition of poly(UUAC) to a cell-free protein-synthesizing system that does not require a start codon? Enter an amino acid sequence of four amino acids using the three-letter abbreviations. Polypeptide sequence: Poly( -3' Glu-Leu-Val-Cys-Lys-CysMRNA CODONS RESPONSIBLE FOR LINING UP EACH OF THE 20 AMINO ACIDS Amino Acid Code-End of the MRNA Codons* (anticodon) tRNA Alanine GCU Arginine Asparagine Aspartic Acid Cysteine Glutamic Acid AGA AAU GAU UGU GAA Glutamine CAA Glycine Histidine GGU CAU Isoleucine AUU Leucine CUU Lysine Methionine AAA AUG Phenylalanine Proline UUU CCU Serine UCU Threonine ACU Tryptophan Tyrosine Valine UGG UAU GUA * There are 64 codons. Some amino acids have several mRNA codons. There is, however, no overlap of codes. 1. You should be able to fill in the 3-letter "code-end" of the tRNA molecules in the table above. Remember, in RNA A pairs with U, and G pairs with C. There is no thymine. Fill in the table.
- 5'-TAGCTGATCGAATATGCGGTCTCTATCTTCGTAGACGA-3' 3'-ATCGACTAGCTTATACGCCAGAGATAGAAGCATCTGCT -5' Determine the amino acids that will be encoded by this sequence Second letter First letter U C A G U UUU Phe UUC UUA UUG Leu CUU CUC CUA CUG Leu GUU GUC GUA GUG Val UCU UCC UCA UCGJ AUU AUC lle AUA ACA AUG Met ACG CCU CCC C CCA CCG ACU ACC GCU GCC GCA GCG Ser - Pro Thr Ala A UGU UACTyr Cys UGC. UAA Stop UGA Stop A UAG Stop UGG Trp G CAC His CAA Gin CAG GAUT GAC Asp GAA AAU Asn ACC Ser AGU AAG LYS AA Glu GAGJ Oa. N-Met-Arg - Ser-Leu-Ser - Ser-C Ob. N-Met-Pro-Arg - Asn-Asp - Ser-C d. N-Met-Lys - Val-Glu-Ala-C Oc. N-Asp-Pro-Lys - Ser - Val-Ile-C Oe. N- Met-Ala-Asp-Pro-Lys - Ser-C G CGU CGC CGA CGG AGA AGG. GGU GGC GGA GGG Arg SCAO Gly U UCAG UUA DUAG Arg G Third letter 135' UGG CAA UCC UAC GAU 3' - 1. Here is the MRNA sequence from a section of a gene (it is the middle of the sequence, so it has no AUG). What is the template sequence of this gene? - 2. Are any of these codons in the MRNA non-degenerate? If so, indicate which one. e 3. 4 a) Translate this mRNA section. Give the 3 letter codes for the amino acids. b) Indicate on the peptide which is the C terminus and which is the N terminus. e 4. Is it possible for a single base pair substitution to cause a truncation in this peptide? If so, e explain how. e 5. Write out the sequence of the anticodon in the tRNA that would bind to the fourth codon in the e MRNA. e 6. Write out a possible miRNA that could regulate the expression of this geneFirst Letter A G U с 22. Using the provided "Genetic Code-Reference" answer the following question. Based on the following DNA template strand, write out the amino acid chain produced. 23. Consider the following mRNA base codon sequence 5'-AUC-GAA-3' and the provided "Genetic Code-Reference". Genetic Code-Reference UUU UUC UUA UUG CUU CUC CUA CUG (mutated or silent) (mutated or silent) b. Briefly explain your reasoning for each. (be sure to include both parts) AULLY AUU a. Label which of the following would result in a mutated amino acid sequence or a silent mutation. (May help to first determine the original amino acid sequence, then compare to mutations) U Phe mRNA codon sequence: anticodon sequence: amino acid sequence: Leu Leu 5'-AUA-GAA-3' Val 5'- AUC-GAC-3' AUC Ille AUA AUAJ *AUG Met/Start GUU GUC GUA GUG UCU UCC UCA UCG) CCU) CCC ccc CCA 000 CCG ACU ACU ACC ACA ACG, C GCU GCC GCA GCG Second Letter Ser Pro Thr 3'-CAA-GTC-TGT-5' Ala UAU UAC) Tyr Туг A **UAA Stop UAG Stop CAU] CACJ…
- 41. The following 9 TRNAS have anticodon loop regions that base pair with the mRNA in the ribosome. Using your knowledge of tRNA-MRNA base pairing and the genetic code chart (+lecture slides), indicate the MRNA codon message being read by the ribosome as well as the1-letter amino acids that is generated. Anticodon Anticodon Anticodon Anticodon 4 Anticodon Anticodon 6. 2 5'-IAG-3' 5'-UAU-3' 5'-АAА-3' 5'-CUC-3' 5'-GAU-3' 5'-AGA-3' codon MRNA 5'-__-3' 5' 3' 5' 3' 5' 3' 5' 3' 5' 3' 1 letter amino acid Anticodon Anticodon Anticodon 8 7 5'-CCG-3' 5'-GUU-3' 5'-CGC-3' codon 5'-__-3' 5' 3' 5' _3' mRNA 1 letter amino acidDetermine the sequence of a polypeptide treated with trypsin and chimotripsine. Below are the fragments generated with each treatment. Determine the original sequence for both fragmentations (reduerde that they must be equal in the order of amino acids) Quimotripsina 1. Leu-His-Lys-Gln-Ala-Asn-Gln-Ser-Gly-Gly-Gly-Pro-Ser 1. Gln-Gln-Ala-Gln-His-Leu-Arg-Ala-Cys-Gln-Gln-Trp 2. Arg-lle-Pro-Lys-Cys-Arg-Lys-Phe Trypsin 1. Arg 2. Ala-Cys-Gln-GIn-Trp-Leu-His-Lys 3. Cys-Arg 4. Gln-Ala-Asn-Gln-Ser-Gly-Gly-Gly- Pro-Ser 5. lle-Pro-Lys 6. Light 7. Phe-Gin-Gln-Ala-Gln-His-Leu-ArgMRNA CODONS RESPONSIBLE FOR LINING UP EACH OF THE 20 AMINO ACIDS Code-End of the Amino Acid MRNA Codons* (anticodon) tRNA Alanine GCU AGA Arginine Asparagine Aspartic Acid Cysteine Glutamic Acid Glutamine Glycine Histidine AAU GAU UGU GAA CAA GGU CAU AUU CUU AAA AUG Isoleucine Leucine Lysine Methionine UUU Phenylalanine Proline CCU UCU Serine ACU UGG Threonine Tryptophan Tyrosine Valine UAU GUA There are 64 codons. Some amino acids have several mRNA codor There is, however, no overlap of codes.