If the free haul area is between 4+30 and 14+30, what is the average haul distance (ft) for the net volume of material taken from the section between station 2+60 and 3+00?
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- Net Cumulative Yardage 5000 ● 4000 3000 2000 1000 -1000 -2000 -3000 -4000 -5000 None of these. 11.7 6.0 O 8.0 5.0 Given the Mass Haul Diagram above and the following information: Excavation Cost: $4.25/cu. yd. Borrow Cost: $4.50/cu. yd. Overhaul Cost: $0.75/sta*cu. yd. Free Haul Limit: 600 ft. Compute the limit of economic haul: O 12.0 -3,000 1,500 5 2,100 6.0 8.0 10 3,500 + 7.1 2,100 1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25If the free haul area is between 4+30 and 14+30, what is the average haul distance (ft) for the net volume of material taken from the section between station 2+60 and 3+00? Response Feedback: The average distance between 2+60 and 3+00 is 20 ft. Add that to the distance from 3+00 to the free haul area, which begins at 4+30.Given the following requirements for a site project and calculate the freehaul volume? • The total haul distance is between station 9+63 and 15+21. Freehaul distance is between station 10+39 and 14+56 • Overhaul is approximately 642186 CY-ft.
- Limit of economic haul is 450 m. not 50m. Thanks!Net Cumulative Yardage ● 5000 4000 3000 2000 C 1000 -1000 -2000 -3000 -4000 -5000 O 8.0 Compute the limit of economic haul: O None of these. 9.2 5.0 Given the Mass Haul Diagram above and the following information: Excavation Cost: $4.00/cu. yd. Borrow Cost: $3.25/cu. yd. Overhaul Cost: $1.25/sta*cu. yd. Free Haul Limit: 600 ft. 6.0 -3,000 9.4 1,500 10 5 2,100 Mass Diagram 6.0 8.0 10 3,500 + 7.1 2,100 1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25Net Cumulative Yardage ● 5000 ● 4000 3000 2000 1000 -1000 -2000 -3000 -4000 -5000 0 O $34,000.00 Compute the total excavation cost: $10,000.00 Given the Mass Haul Diagram above and the following information: Excavation Cost: $4.00/cu. yd. Borrow Cost: $4.25/cu. yd. Overhaul Cost: $1.25/sta*cu. yd. Free Haul Limit: 600 ft. $32,000.00 5.0 None of these. -3,000 O $26,000.00 1,500 5 2,100 Mass Diagram 6.0 8.0 10 3,500 7.1 2,100 -1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25
- In a site balancing project, the total haul distance starts from Sta. 2+720 and ends in Sta. 4+450. The freehaul distance starts 430 m. away from the starting station of the total haul distance and ends before the total haul distance which is also at a distance of 430 m. a. Get the total haul distance b. Locate the starting and end stations of the free haul distance c. Get the overhaul distance. d. Get the freehaul volume if it is estimated that the overhaul is approximately 5264 m3-m. . e. Sketch the mass diagram based on the given.Net Cumulative Yardage 5000 ● 4000 3000 2000 1000 -1000 -2000 -3000 -4000 -5000 $10,590.00 Compute the total overhaul cost: O None of these. Given the Mass Haul Diagram above and the following information: Excavation Cost: $3.50/cu. yd. Borrow Cost: $3.75/cu.yd. Overhaul Cost: $1.50/sta*cu. yd. ● Free Haul Limit: 600 ft. O $1,590.00 5.0 O $600.00 -3,000 O $990.00 1,500 5 2,100 Mass Diagram 6.0 8.0 10 3,500 + 7.1 2,100 1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25Q3: In an earth work site, the total haul distance is between station 2+94 and 4+64. The free haul distance is between station 3+17 and 4+44. The overhaul is about 163662 m3.station. What is the free haul volume?
- Given the following Mass-Haul Diagram: Mass Diagram 5000 4000 3,500 3000 2,100 6.0 2.100 7.0 2000 8.0 1,500 1,500 8.0 ------ 1000 -1,100 - 7.1 6.0 750 5.0 0. -1000 3-2000 -3000 -3,000 -4000 -5000 10 15 20 25 Stations Limit of free haul = 600 ft Price of excavation = $3.50 Price of borrow = $3.75 Overhaul = $1.50 What is the total cost in borrow to the nearest dollar? O $0 O $2,625 $2,813 $5,625 O Non Net Cumulative Yardage2. Determine the total cost of earthworks and draw the mass haul diagram of a highway section having the cumulative volume shown in the table below: Station No. ㅇ 5 9 13 15 Cumulative |Volume Given that cost of overhaul = Php 750.00/m²station, cost of borrow = Php 2500.00/m², cost of freehaul = Php 1250.00/m’, and the free haul distance = 9 stations. ㅇ 250 350 220 0 %3D %3D %3D %3DThe following net accumulations were calculated. The free haul area begins at station 4+30 and continues to 14+30. If the overhaul is charged at $10/yd³ station, what is the total overhaul cost ($)? Round to the nearest cent. from station to station net accumulation, yd³ 2+60 3+00 3.85 3+00 4+00 5.85 4+00 4+30 8.35 Response Feedback: 10x8.35x0.9281