In a queueing system, customers arrive once every 6 seconds (standard deviation = 5) and services take 5 seconds (standard deviation - 4). (Do nót round intermediate calculations. Round your answer to three decimal places.) customers What is the average number of customers in the queue?
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A: Given, a = 1 customer every 6 min = 1/6 s = 1 customer every 4 min = 1/4 Utilization = (1/6)/(1/4) =…
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- In a queueing system, customers arrive once every 4 hours (standard deviation = 7) and services take 3 hours (standard deviation = 4.9). (Do not round intermediate calculations. Round your answer to three decimal places.) What is the average number of customers in the queue? customersIn a queueing system, customers arrive once every 4 seconds (standard deviation = 4) and services take 2 seconds (standard deviation = 4.3). (Do not round intermediate calculations. Round your answer to three decimal places.) What is the average number of customers in the queue? customersIn a queueing system, customers arrive once every 6 minutes (standard deviation = 7) and services take 4 minutes (standard deviation = 4,6). (Do not round intermediate calculations. Round your answer to three decimal places.) What is the average number of customers in the system? customers
- In a queueing system, customers arrive once every 4 minutes (standard deviation = 7) and services take 3 minutes (standard deviation = 5.5). (Do not round intermediate calculations. Round your answer to three decimal places.) What is the average time a customer will spend in the queue (in minutes)? minutesIn a queueing system, customers arrive once every 5 minutes (standard deviation = 7) and services take 3 minutes (standard deviation = 6.8). (Do not round intermediate calculations. Round your answer to three decimal places.) What is the average time a customer will spend in the system (in minutes)? minutesIn a queueing system, customers arrive once every 3 hours (standard devlation = 4) and services take 2 hours (standard deviation = 6.2). (Do not round intermediate calculations. Round your answer to three decimal places.) What is the average number of customers in the system? customers
- In a queueing system, customers arrive once every 4 seconds (standard deviation = 4) and services take 2 seconds (standard deviation = 4.3). (Do not round intermediate calculations. Round your answer to three decimal places.) What is the average time a customer will spend in the queue (in seconds)? secondsIn a queueing system, customers arrive once every 3 hours (standard deviation = 4) and services take 2 hours (standard devlation = 6.2). (Do not round intermediate calculations. Round your answer to three decimal places.) What is the average time a customer will spend in the system (in hours)? hours