Part A: In the above figure, a light beam shines through air and then strikes a mirror, making an angle theta = 23.2 degrees with respect to the vertical, as shown. The reflected beam then strikes a pane of glass of thickness h = 1.32 cm, located a distance y= 57.6 cm from the mirror, and then exits the glass pane at the bottom, a horizontal distance x cm away from where it struck the mirror. What is the value of x? Part B: This time, the incident ray is coming in from water (n=1.33) rather than air. And this time, theta = 37.5 degrees, y = 27.1 cm and h = 1.34 cm. What is x now?

Part A: In the above figure, a light beam shines through air and then strikes a mirror, making an angle theta = 23.2 degrees with respect to the vertical, as shown. The reflected beam then strikes a pane of glass of thickness h = 1.32 cm, located a distance y= 57.6 cm from the mirror, and then exits the glass pane at the bottom, a horizontal distance x cm away from where it struck the mirror. What is the value of x? Part B: This time, the incident ray is coming in from water (n=1.33) rather than air. And this time, theta = 37.5 degrees, y = 27.1 cm and h = 1.34 cm. What is x now?

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter9: Solids And Fluids

Section: Chapter Questions

Problem 4WUE

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