Question 1: A sheet pile wall isolates two flooded areas as shown in Figure 1. The head loss ÿH generates a downward flow on the upstream side and an upward flow on the downstream side. If the saturated soil has a density of 2375 kg/m3 on either side of the curtain, calculate the effective stress at points A and B. 1 m 4 m 5 m 7.5 m 12 = 150 kPa Figure 2 Figure 1- Question 2: Using the data in Figure 2, calculate the vertical stress induced by the loading of the foundations at point A, located 2 m deep, halfway between the two footings. Use the figure 5 to find the coefficient of influence. Representat B 6 m 2 m 3m → 1 m 2 111 311 91 = 125 kPa

Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN:9781305635180
Author:Braja M. Das, Nagaratnam Sivakugan
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Chapter7: Seepage
Section: Chapter Questions
Problem 7.2P
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Question 1:
A sheet pile wall isolates two flooded areas as shown in Figure 1. The head loss ÿH generates a downward flow on
the upstream side and an upward flow on the downstream side. If the saturated soil has a density of 2375 kg/m3 on
either side of the curtain, calculate the effective stress at points A and B.
4 m
1 m
Good work!
5 m
7.5 m
Figure 1-
92 = 150 kPa
Во
Question 2:
Using the data in Figure 2, calculate the vertical stress induced by the loading of the
foundations at point A, located 2 m deep, halfway between the two footings. Use the
figure 5 to find the coefficient of influence.
2 m
6 m
1 m
2 11
3m →
Figure 2 - Representation of the foundations of question 1
311
q=
125 kPa
February 1
Transcribed Image Text:Question 1: A sheet pile wall isolates two flooded areas as shown in Figure 1. The head loss ÿH generates a downward flow on the upstream side and an upward flow on the downstream side. If the saturated soil has a density of 2375 kg/m3 on either side of the curtain, calculate the effective stress at points A and B. 4 m 1 m Good work! 5 m 7.5 m Figure 1- 92 = 150 kPa Во Question 2: Using the data in Figure 2, calculate the vertical stress induced by the loading of the foundations at point A, located 2 m deep, halfway between the two footings. Use the figure 5 to find the coefficient of influence. 2 m 6 m 1 m 2 11 3m → Figure 2 - Representation of the foundations of question 1 311 q= 125 kPa February 1
Influence value, /
0.01
0.16
0.14
0.12
0.10
0.08
0.06
0.04
0.02
0
Load qo per unit of area
M=
m and n are interchangeable
0₂= qol
0.02
0.01
m=0.5,
m=0.0
0.02
0.04
3=6
0.04
0.1
m = 1.0
m= 2.0
0.1
0.2 0.3
E
0.6
0.28
0.26
0.24
0.22
0.20
0.18
0.5
Figure 5
1
m = 0.5
m=1.8
0.2 0.3 0.5 0.8 1
Value of n
2
m=2.0
+-
2
3 4
m = 2.5
29
3
6 8 10
m = 1.2
m = 1.0
m=0.9
m=0.8
m=0.7
m=0.6
m = 0.5
m = 0.4
4
m=0.3
m = 0.2
m=0.1
m=0.0
6
0.28
0.26
8 10
0.24
m= 1.6
+ m=1.4
0.22
0.20
0.18
0
0.16
0.14
0.12
0.10
0.08
0.06
0.04
0.02
m=∞
m=3.0
Transcribed Image Text:Influence value, / 0.01 0.16 0.14 0.12 0.10 0.08 0.06 0.04 0.02 0 Load qo per unit of area M= m and n are interchangeable 0₂= qol 0.02 0.01 m=0.5, m=0.0 0.02 0.04 3=6 0.04 0.1 m = 1.0 m= 2.0 0.1 0.2 0.3 E 0.6 0.28 0.26 0.24 0.22 0.20 0.18 0.5 Figure 5 1 m = 0.5 m=1.8 0.2 0.3 0.5 0.8 1 Value of n 2 m=2.0 +- 2 3 4 m = 2.5 29 3 6 8 10 m = 1.2 m = 1.0 m=0.9 m=0.8 m=0.7 m=0.6 m = 0.5 m = 0.4 4 m=0.3 m = 0.2 m=0.1 m=0.0 6 0.28 0.26 8 10 0.24 m= 1.6 + m=1.4 0.22 0.20 0.18 0 0.16 0.14 0.12 0.10 0.08 0.06 0.04 0.02 m=∞ m=3.0
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