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Sample | Physical Appearance |
0.1 M Na2CO3 |
|
0.1 M CaCl2 |
|
Na2CO3 + CaCl2 mixture |
|
Part II filtrate + CaCl2 |
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- #9: This unknown contains 51.90 % C and 9.80 % H by mass with the remainder being an unknown element (you have to figure out what element). 100- Base 80 60 90 Relative Intensity 100 TRANSNETTANCE 40 20- O 4000 10 20 3000 30 peak 656 50 40 m/z REVENUTER 60 1300 peak 094 92-37= 90-35= C) 70 80 1000 90A solution is made by the following steps. 1. 90.0 mg ± 0.2 mg of dye with molar mass 685.79 g/mol ± 0.02 g/mol is dissolved in a 100.00 mL ± 0.05 mL volumetric flask with water to make solution #1. 2. 25.00 mL of solution 1 is added 100.00 mL ± 0.05 mL volumetric flask with water to make solution #2. 3. 25.00 mL of solution 2 is added 100.00 mL ± 0.05 mL volumetric flask with water to make solution #3. A.) If you have available a 5.00 mL ± 0.01 mL, 10.00 mL ± 0.05 mL, and 25.00 mL± 0.15 mL. Describe how to use the pipettes and the directions above to make the most precise solution #3. Explain why this is the most precise method. B.) Determine the concentration ± absolute error of solution #3 in molarity. Explain the calculations you needed to do. C.) Using Beer's law (10% error), solution #3 is found to be 2.0 ✕ 10-5 M. Was solution #3 likely made within the expected error. Explain.+2 Pb Thallium Lead 200.592 2818 32 182 1832 18 1 204.383 207.2 28 18 32 10 2818 32 18 3 111 112 +2 Mt Ds Hassium Meitnerium Darm (264] 32 32 122 2818 32 32 13 2 28 18 32 32 [269] 59 15. NaOH Ba(NO), (1)balanced eanation (10101lm介 10nice (6) Total mot ianic eanation (d)net lonic eqnoition
- CHM120 Park Lab Notebook F20 Alessandra Fernandez Cuadr Desktop App O Tell me what you want to do m<而< 三 A Styles v K Tags v abc v HCI Ba(NO3)2 K2CO3 AgNO3 Pb(NO3)2 Na,so KI HNO3 4 HCI Ba(NO No 3)2 reaction K2CO3 Evolution of gas White precipitate AGNO3 White No White precipitate reaction precipitate KI No No No White reaction reaction reaction precipitate Pb(NO White 3)2 No White No Yellow precipitate reaction precipitate reaction precipitate HNO3 Evolution of No Evolution No No No gas reaction of gas reaction reaction reaction Na,so No reaction White No White No White No precipitate reaction precipitate reaction precipitate reaction 4 2. Along with written observations, write 1) the molecular equation, 2) complete ionic and 3) net ionic equations for each reaction. stv X Search or type URL * &Beaker 0.00200 M Fe(NO3)3, mL 0.00200 M NaSCN, mL total volume, mL 1 3.000 2.000 10.00 2 3.000 3.000 10.00 3 3.000 4.000 10.00 4 3.000 5.000 10.00 5 (blank) 3.000 0.000 10.00 In Solutions 1-4 you are adding successively larger volumes of 0.00200M SCN- to the Fe3+ solution and diluting to 10.00 ml. Calculate the final diluted molarity of SCN- in solution #1 Your answer should have 3 sig figs =4) __ H2 + O2 0 H20 HCI O Pb(OH)2 + AIBR3 + Al2(SO4)3 5) H20 + PbCl2 6). K2SO4 O KBr + 7) CH4 + O2 0 CO2 + H2O 8) _ C3H8 + 02 O2 0 СО2 + H20 9). C3H18 + O2 CO2 + H20 10). FeCl3 + NaOH Fe(OH)3 + Nac
- A 2.0 g of MgCO3 was dissolved and diluted to exactly 500-mL volumetric flask. If 50-mL aliquot was used in the analysis, what is the weight of MgCO3 present in the aliquot sample5) 3) 2) Percentage Composition Worksheet Give the % composition of all elements in these compounds. Show all work! 1) ammonium sulfite % N % H sodium bromide aluminum acetate % Al % C 4) copper (II) hydroxide % S % O magnesium carbonate % H % O % Na % Br M_ For chemistry help, visit http://www.chemfiesta.com % Cu % O % H % Mg % C % O O Ma 9.8 ebinayo muiaestog Llobiriqaoriq muinul (Ot 2 (8 etellua (III) lexoin Ⓒ2000 Cavalcade Publishing - All Rights ReservedMass of CaCO3= 0.3185 g Trial VCaCO3 1 25.00 mL 2 25.00 mL 3 25.00 mL Vi (mL) 0.00 0.10 0.50 V EDTA Vf V used (mL) 32.75 32.15 32.83 Average M EDTA MEDTA
- Mla pnc.com/women Mail - Whi x O Grades for x Course Ho X G oxide cont X G Exercise 4.x E 4 - Molecu x O Bananas a X 1.84 x 10- x + envellum.ecollege.com/course.html?courseld 16985674&OpenVellumHMAC=a0b841caaee7feddab1623a6c83a92c0#10001 Review | Constants I Periodic Table Percent composition refers to the mass percent of each element in a compound: mass of element Part A mass percent = x 100% mass of compound > For example, the percent composition of water, H2O. is 11.2% hydrogen and 88.8% oxygen. Therefore, a 100-g sample of water contains 11.2 g of hydrogen atoms and 88.8 g of oxygen atoms. A hydrocarbon is a compound that contains mostly carbon and hydrogen. Calculate the percent composition (by mass) of the following hydrocarbon: CH22 Enter the percentages of carbon and hydrogen numerically to four significant figures, separated by commas. The periodic table will be useful when doing this problem. You can access a periodic table by clicking the "Tools" link in the upper right…What is the concentration (mg/L) of lead from a water sample with an absorbance of 0.413? Pls answer thank you so muchQ3/ A) 0.63 g of a sample containing Na,CO3, NaHCO, and inert impurities is titrated with 0.2 M HCI, requiring 17.2 mL to reach the phenolphthalein end point and a total of 43.5 mL to reach the modified methyl orange end point, How many grams NazCO3 and NaHCO, are in the mixture?