Solve the following initial value problem using Laplace transform: d²y dt² 18 dy where +45y = g(t), y (0) = -1/3, t-o=9, 3 0 < t < 6 6 6 ≤t g (t) Let Y (s) be the Laplace transform of the solution y (t). Then evaluate Y(-1/3) y (-1/3). Y(−1/3) · y (−1/3) =( )

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