Suppose f : A →→ B is an injective function. Show that there is a function g : B→ A such that gof= idA. Here, idA: A → A is the identity function on A, i.e., the function that satisfies idд(a) = a for all a € A. (Assume f is non-trivial, i.e., A = 0!)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.4: Definition Of Function
Problem 54E
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Suppose f: AB is an injective function. Show that there is a function g: B → A such that
go f = idA. Here, idA: A → A is the identity function on A, i.e., the function that satisfies idÃ(a) = a
for all a € A. (Assume f is non-trivial, i.e., A = 0!)
Transcribed Image Text:Suppose f: AB is an injective function. Show that there is a function g: B → A such that go f = idA. Here, idA: A → A is the identity function on A, i.e., the function that satisfies idÃ(a) = a for all a € A. (Assume f is non-trivial, i.e., A = 0!)
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