The steel beam AB has a uniformly distributed load (UDL) w1 = 6 kN/m acting along its full length L1 = 7 m. The section properties of the steel beam are given below. The Grade S275 universal column (UC) is designated as Class 3, elastic, in bending The UC has a flange thickness t₁ = 12.8 mm Its plastic section moduli are Wply-y = 1,600 cm³ and Wpl z-z = 183 cm³ Its second moment of area are I y-y = 13,523 cm4 and I z-z = 726 cm4 Calculate the deflection at mid-span in mm an give your answer to one decimal place.
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- Asiacell|Asiacel K/s Asiacell For simply supported beam with rectangular cross section shown, determine the values and location of the maximum tensile and compressive bending * stresses 1000 lb 400 lb/ft 6 in DV 8 in 10 ft RA RpDetermine the axial compressive strength of an HSS steel with a length of 4.6m with respect to the principal axis. Use Fy = 318 MPa. Section Properties: A = 1742 mm2 ly = 3.29 x 106 mm4 Ix = 9.53 x 106 mm4 Answers: Pnmax = 238. 358 kW CIVIL ENGINEERING STEEL DESIGN 203.2 -3.2 -101.6- -3.2 TAn I-section with two cover plates is used as tension member and is subjected to a load of 120 t over a length of 16 m. If the allowable tensile stress is 15000 kg/cm², is the member design safe? If 9821.6 cm4, so, find the factor of safety. Use ISWB 300@ 48.1 kg/m, A = 61.33 cm², Ixx Ivy 990.1 cm4. There are two rows of fasteners in each flange, thus making atleast two holes in one section. The fastener diameter is 22 mm, cover plate size 260 mm x 8 mm, flange thickness of l-section = 10 mm. The center of fastener is located at 60 mm from center line of the l-section. = =
- Determine the safe load of the column section shown, if it has a yield strength of 25 MPa. E = 200000 MPa. Use NSCP Specifications. Fyz248 mpa Properties of Channel Section d = 305 mm t₂ = 7.2 mm A = 3929 mm² t₁ = 12.7 mm Ix=53.7 x 10mm¹ x = 117 mm Properties of W 460 x 74 A = 9450 mm² b = 190 mm ly= 1.61 x 10 mm x = 17.7 mm tw = 9.0 mm rx = 188 mm ry = 41.9 mm d = 457 mm tr = 14.5 mm Ix = 333 x 10 mm Iy = 16.6 x 10mm* 7.21 When the height of column is 6 m. When the height of column is 10 m. Assume K= 1.0 457 CIVIL ENGINEERING- STEEL DESIGNA steel column is pin connected at the top and bottom which is laterally braced and subjected to transverse loading. It carries an axial load of 800 kN and a 70 kN-m moment. Use ASD. The steel section has the following properties: A = 13000 mm² r = 94 mm Ix = 300 x 106 mm4 Sx = 1200 x 103 mm³ L = 3.6 m Yield stress Fy = 248 MPa Axial compressive stress that would be permitted if axial force alone existed, Fa = 115 MPa Compressive bending stress that would be permitted if bending moment alone existed, Fb = 148 MPa Members subjected to both axial compression and bending stresses shall be proportioned to satisfy the following requirements: Mry + 9 Mex Mey Determine the axial compressive stress if axial load only existed. Pr 8 Mrx + Pe 75.82 MPa 61.54 MPa 33.96 MPa 16.25 MPa Determine the bending stress if bending moment alone existed. 76.25 MPa O58.33 MPa 13.33 MPa ≤ 1.0 16.59 MPa Determine the value of both axial and bending moment interaction value, considering the amplification due to…Two T-shape sections are welded together to create a composite l-beam section as shown below. Determine the safely uniform load w (kN/m) that the beam can carry throughout its entire span. 270mm 30mm 20mm 160mm Welded Joint 130mm 30mm 135mm Beam Length = 4 m Consider the following stresses: fb(T) 3 125 МPа fb(C) = 130 MPa x at the welded joint = 20 MPa Find: 1. The Neutral Axis from the base 2. moment of inertia with respect to the horizontal centroidal axis 3. Q at the welded joint 4. Considering the maximum flexural stress in tension, WNAX is equal to KN/m. 5. Considering the maximum flexural stress in compression, WMAX, is equal to 6. Considering the stress at the welded joint, wMex is equal to kN/m.
- A W16X31 A992 steel is used as a beam. The beam has a continuous lateral support. The uniformly distributed load shown in the figure is a service load that consists of 50% dead load (included the beam weight) and 50% live load. Using LRFD, determine the following? Note: A992 STEEL Fy = 50 ksi Ag = 9.13 in^2 Zx = 54.0 in^3 a. Ultimate (Governing Load Combo) Maximum Negative Moment (at support) in kips-ft b. Ultimate (Governing Load Combo) Maximum Positive Moment (at midspan) in kips-ft c. The Flexural Capacity of the Beam in kips-ft d. Demand Capacity Ratio of Beam really need answer please2. From the tabulation below determine if the column is safe to carry axial & bending load Yield stress of structural steel is 248 MPa. Modulus of elasticity is 200,000 MPa Service Load: Pa = bending moment Mux = Muy = 16 kN.m (LRFD load combination) bending moment Mx = My = 12 kN.m (ASD load combination) unsupported height of column = 3.5 m assume K = 1.0 Pu = AISC Designation 8x8 150 kN 200 KN (Square sections) wall thickness mm Area rx =ry Weight/m Ag (mm²) mm 88.28 11,226 10,258 9,290 7,161 6,039 4,897 3,723 15.88 14.29 80.61 12.7 72.7 9.53 56.09 7.94 47.36 6.35 38.42 4.76 29.21 75.18 76.2 76.96 78.48 79.25 80.01 80.77 Ix 105 4 mm Sx 10³ 3 mm 63.68 627.62 59.52 585.02 54.53 539.13 44.12 432.62 37.84 371.99 31.26 308.08 24.22 239.25 Jx 10²³ 4 mm Zx 10³ 3 mm 107.39 773.47 99.06 714.48 90.32 650.57 70.76 512.92 60.35 437.53 49.12 358.88 37.71 275.3PROBLEM 2: Determine the smallest safe cross-sectional areas, in mm?, of members Cl and CD for the wooden truss shown below. The working stresses are 10 MPa in tension and 8 MPa in compression. (The working stress in compression is reduced due to the danger of buckling.) 8 kN 4 kN 4 kN FINAL ANSWERS 4 kN 4 kN 4 kN - 4 kN Acı mm? K 3.5 m ACD mm2 A в с D E F PA - 6 @ 4 m = 24 m
- Rolled steel section ISWB 300 is used as a column of height 6 m, fixed at base and pinned at top. Find the permissible compressive load on the column using the table of permissible compressive stresses as given in the table below: Cross-section properties of ISWB 300 section are as follows: Area of cross-section = 6133 mm² Flange width= 200 mm 10 mm 7.4 mm 2 dac λ Osc Flange thickness Web thickness = 50 132 13 57 2 = slenderness ratio 60 122 = 1xx Lyy = = 70 112 98.216 x 106 mm4 9.9 x 106 mm4 80 101 90 100 90 80 140 150 160 170 180 51 45 41 37 33 ac = allowable compressive stress in MPa Use linear interpolation for intermediate values of λ. 110 72 190 30 120 64 200 28Q2 A W6 x 15 structural steel column is 24 ft tall and is fixed at its base and top. It is braced (horizontally) at the midspan. These braces are pin-connected to the column's web. Determine the load that the column can support so that it does not buckle nor the material exceeds the yield stress. Use the undermentioned data: = 29 (10) ksi Oy = 60 ksi I = 29.1 in %3D Iy = 9.32 inProblem2. The compression member is shown in figure. Find the following: a. The Euler stress Fe. b. The buckling stress Fcr c. The design strength d. The allowable strength e. Does the member satisfactorily meet the design requirements? Why? HSS 8x 8x4 ASTM AS00, Grade B steel (Fy = 46 ksi) 15'