Yo m/s 500 V 4. (a)In the figure, a proton is fired with an initial speed (vo) of 100000 m/s from the midpoint of the capacitor toward the positive plate as shown. The plates are 0.5 m. apart. i.Find the location (in cm) where the proton stops and turns around (use x=0 as the location of the negative plate). 030.2011.8 063.8 098.5 026.3 045.3 ii.What is the potential (in V) at that location? 0638 0985 0118 0453 0302 0263 iii.What is the proton's speed (in m/s) when it reaches the 150 V location? 01.71e+05 03.60e+05 05.57e+05 01.49e+05 066600 02.56e+05 iii.If an electron is fired from the positive plate with an initial velocity that is 90 times faster than the initial velocity of the proton, how far (in cm) from the OV plate will it stop? 040.4 026.9 056.8 023.4 087.8 010.5 (b)Consider two charges of charge -5e-09 C nailed in place on the y-axis straddling the origin (one charge 0.006 m above the origin and one charge 0.006 m below the origin). A proton is at the origin and it is launched directly to the right (along the x-axis). i.What is the escape speed (in m/s) of the proton (middle charge)? (Again, assume the two outer charges are fixed in place) 01.47e+06 01.70e+06 O3.58e+06 06.61e+05 05.53e+06 02.54e+06 ii.If the proton (middle charge) is launch with half of the escape speed, how far away (in m) from its starting point will it stop and turn around? 00.0079400.00460 00.00206 00.00529 00.0112 00.0173 (c) An electric dipole consists of 0.003 kg spheres charged to +3e-09 C at the ends of a 0.19 m long non-conducting rod of mass 0.009 kg (don't try to look up "electric dipole", it won t help you. For the sake of this problem, it is just a fancy word for what I just described). The dipole rotates on a frictionless pivot at its center. The dipole is held perpendicular to a uniform electric field with a field strength 1000 V/m, then released. i.What is the dipole's angular velocity (in rad/s) at the instant it is aligned with the electric field? (HINT: Look up the moment of inertia of the rotating rod about its center and don't forget the rotational kinetic energy term (along with the other terms) when you set up your conservation of energy problem). 00.0462 00.250 00.386 O0.103 O0.118 00.178 (d) Four 1e-08 C charges are held in location to form a perfect square with sides of length 0.04 m. Two of the charges from opposing corners are released simultaneously, the other two are held in place. The mass of each charge is 0.008 kg.. i.How fast (in m/s) will the two released charges be moving when they are far, far away from their original location? O0.115 00.0449 00.173 O0.100 O0.375 00.243

Yo m/s 500 V 4. (a)In the figure, a proton is fired with an initial speed (vo) of 100000 m/s from the midpoint of the capacitor toward the positive plate as shown. The plates are 0.5 m. apart. i.Find the location (in cm) where the proton stops and turns around (use x=0 as the location of the negative plate). 030.2011.8 063.8 098.5 026.3 045.3 ii.What is the potential (in V) at that location? 0638 0985 0118 0453 0302 0263 iii.What is the proton's speed (in m/s) when it reaches the 150 V location? 01.71e+05 03.60e+05 05.57e+05 01.49e+05 066600 02.56e+05 iii.If an electron is fired from the positive plate with an initial velocity that is 90 times faster than the initial velocity of the proton, how far (in cm) from the OV plate will it stop? 040.4 026.9 056.8 023.4 087.8 010.5 (b)Consider two charges of charge -5e-09 C nailed in place on the y-axis straddling the origin (one charge 0.006 m above the origin and one charge 0.006 m below the origin). A proton is at the origin and it is launched directly to the right (along the x-axis). i.What is the escape speed (in m/s) of the proton (middle charge)? (Again, assume the two outer charges are fixed in place) 01.47e+06 01.70e+06 O3.58e+06 06.61e+05 05.53e+06 02.54e+06 ii.If the proton (middle charge) is launch with half of the escape speed, how far away (in m) from its starting point will it stop and turn around? 00.0079400.00460 00.00206 00.00529 00.0112 00.0173 (c) An electric dipole consists of 0.003 kg spheres charged to +3e-09 C at the ends of a 0.19 m long non-conducting rod of mass 0.009 kg (don't try to look up "electric dipole", it won t help you. For the sake of this problem, it is just a fancy word for what I just described). The dipole rotates on a frictionless pivot at its center. The dipole is held perpendicular to a uniform electric field with a field strength 1000 V/m, then released. i.What is the dipole's angular velocity (in rad/s) at the instant it is aligned with the electric field? (HINT: Look up the moment of inertia of the rotating rod about its center and don't forget the rotational kinetic energy term (along with the other terms) when you set up your conservation of energy problem). 00.0462 00.250 00.386 O0.103 O0.118 00.178 (d) Four 1e-08 C charges are held in location to form a perfect square with sides of length 0.04 m. Two of the charges from opposing corners are released simultaneously, the other two are held in place. The mass of each charge is 0.008 kg.. i.How fast (in m/s) will the two released charges be moving when they are far, far away from their original location? O0.115 00.0449 00.173 O0.100 O0.375 00.243

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter26: Electric Potential

Section: Chapter Questions

Problem 67PQ: A charged particle is moved in a uniform electric field between two points, A and B, as depicted in...

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