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You prepare the following MeOH standards from a 2000 ppm stock MeOH solution:
Calibration Blank, 50 ppm, 100 ppm, 150 ppm and 400 ppm and analyze them using the GC-FID. You received the following data:
| Concentration of MeOH (ppm) |
Response (area) of MeOH peak (pA) |
| 0 | 0 |
| 50 | 150 |
| 100 | 320 |
| 150 | 440 |
| 400 | 1100 |
Using the data above, make a properly documented graph of "Response (area)”
versus "Concentration of MeOH (ppm)" and determine the linear working
range (in units of concentration) of MeOH. This graph is to be done using
Excel. Be sure to provide a trendline, formula & R2 value).
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- Sheet 5 From the following data determine the following: Define outlier and then identify the outlier in the data. Determine if the outlier should be kept of discarded from the data. Trial 1 2 3 4 HCl (mL) 22.3 28.4 29.8 29.3 NaOH (mL) 35.2 35.1 34.9 35.0percentage purity of an ibuprofen sample was determined by a reversed phase HPLC method as follows: Y Der ● A calibration curve of peak area versus concentration (ug/mL) of pure ibuprofen was constructed The ibuprofen sample for analysis was prepared by taking 10.0204 g of powder and dissolving it in/1Lbf distilled water (solution A). 1 ml of the latter solution was further diluted to IL with distilled water (solution B). Solution B was analysed by HPLC analysis Results The equation for the best-fit line of the calibration curve is: y=26820x-1323.8. ● The average peak area for the ibuprofen sample (solution B) was 266796.2 Calculate the percentage purity of the ibuprofen powder.25 ml of pickled brine was taken from an apple pickled with vinegar and diluted to 500 ml, 25 ml of this was taken and acidity was determined with 0.2 N (Factor: 1.05) NaOH. In the main trials, 6.3 ml - 6.5 ml - 6.9 ml, respectively, 0.1 ml base was used in the analysis without using the sample.For example, how many ppm is its acidity?
- Felodipine calcium channel blocker standard (0.251mg/ml) and felodipine sample (0.245mg/ml) solutions were prepared and injected to the HPLC. The peak area of felodipine standard is 275428 and the sample is 272982. The potency (purity) of felodipine standard is 98.9%. What is the assay percentage of felodipine? a. 102.23 b. 98.71 c. 101.07 d. 100.42The following data are from the HPLC assay of paracetamol 500 mg tablets using the calibration curve method: - Weight of active ingredient in powdered tablets taken for analysis: 180 mg • Initial extraction volume: 200 mL - Dilution steps: 10 mL into 100 mL, then 5 mL into 100 mL - Linear equation: y = 12000x - 50 %3! - Area of chromatographic peak for sample is 4750. What is the theoretical concentration in final solution in mg/100 mL? (2 decimal places). Please do not write the units, just numerical value. Answer:The concentration of acetylsalicylic acid in an antipyretic tablet was determined by HPLC using a normal calibration curve. Standard solutions of acetylsalicylic acid were prepared and analysed using a 10µL loop. The results obtained for the standards are tabulated below: Conc. of Acetylsalicylic Acid (ppm); Signal (arbitrary units) 50; 6352 100; 12869 150; 19175 200; 25536 250; 31936 To determine the concentration of acetylsalicylic acid in an antipyretic tablet, 10 tablets were weighed (6.500 g total) and crushed to a fine powder using a mortar and pestle. A quantity of powder equal the mass of one tablet was added to a 100 mL volumetric flask. The tablet powder was dissolved with 20 mL of methanol and the flask was made to volume using water. The solution was filtered. A 1.000 ml aliquot was transferred to a 10 ml volumetric flask, which was then made to volume with water. Analysis was conducted using a Bio Sil HL C18, 250mm x 4.6mm column; 5um, with a mobile phase of acetonitrile:…
- The percentage purity of a paracetamol sample was determined by a reversed phase HPLC method as follows: • A calibration curve of peak area versus concentration (ug/mL) of pure paracetamol was constructed The paracetamol sample for analysis was prepared by taking 10.0254 g of powder and dissolving it in IL of distilled water (solution A). 1 mL of the latter solution was further diluted to 1L with distilled water (solution B). Solution B was analysed by HPLC analysis Results • The equation for the best-fit line of the calibration curve is: y = 26811x – 1313.8 The average peak area for the paracetamol sample (solution B) was 266796.2 Calculate the percentage purity of the paracetamol powder.3. This is the standard procedure for determination of nicotine in urine. A 1.00mL sample was placed in a 12mL vial 5-aminoquinoline was added as the internal standard (5 ug). The sample was monitored using mass spectrometry at m/z values for nicotine (84) and the internal standard (144). Given the following data determine the concentration of the two unknown samples Nicotine (ug/L) Area Area 12 0.056 0.059 51 0.402 0.391 102 0.684 0.669 157 1.011 205 Unknown 1 Unknown 2 1.278 0.51 1.18 1.063 1.355 0.53 1.3250 Percentage Red No. 40 Soln 100% 80% 60% 40% Table 4.1: Dilutions of Red No. 40 & Absorbance Volume of Red No. 40 Soln (mL) 10me 8mL опи 4mL Percentage Red No. 40 Soln 100% 80% 60% 40% 20% Volume of DI Water (mL) OML 2mL LIML M UML 8ML Table 4.2: Dilutions of Red No. 40 & Absorbance Concentration Red No. 40 2. Report the wavelength with the maximum absorbance of Red No. 40 dye. Absorbance 20% 2ML Part A: Making a Calibration Curve for Beer's Law 1. Calculate the concentrations of each of your diluted Red No. 40 solutions and add these to Table 4.2. Show at least one sample calculation in the space below. 0.251 0.192 Total Volume 0.181 0·119 0.060 (mL) 10 mL 10 mL 10 mL 10 mL 10 mL
- A chromatographic analysis is performed with a sample containing toluene and benzene. The column length was 25 m and the flow rate 45 mL/min. Solute tR air 1.75 benzene (A) 7.00 1.85 toluene (B) 16.10 1.65 Calculate the theoretical plate height for each peak. Benzene: 109 mm/plate and Toluene 16 mm/plate Benzene: 105 mm/plate and Toluene 49.7 mm/plate Benzene: 172 mm/plate and Toluene 175 mm/plate Benzene: 119 mm/plate and Toluene 181 mm/plateA banned pesticide, DDT, is analyzed through gas chromatography. A DDT standard is diluted accordingly to generate 1.00, 5.00, 10.00, 15.00, 20.00, and 25.00 ppm standards. These standards generate peaks with peak areas of 0.100, 0.210, 0.295, 0.405, O.510, and 0.600, respectively. If a nearby watershed sample is subjected to GC analysis, and the sample generated a 0.175 peak area, what is the concentration of DDT in the sample? 3.12 ppm 4.02 ppm 5.09 ppm 1.65 ppm 3.75 ppm Music off 只If an instrument gives a response of 1240 for a standard containing 8 ppm of a substance, how much if this substance is in a sample that gives a response of 1705? Are any assumptions needed?
