Suppose you are analyzing a haploid E. coli strain and discover that the genes of the lac operon are never transcribed and that the bacteria cannot grow in lactose-containing medium. Provide two possible genotypes for your bacteria that would explain this phenotype .

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Answer 1

Textbook Question

Chapter 20, Problem 20.1CC

Suppose you are analyzing a haploid E. coli strain and discover that the genes of the lac operon are never transcribed and that the bacteria cannot grow in lactose-containing medium. Provide two possible genotypes for your bacteria that would explain this phenotype.

Expert Solution & Answer

Summary Introduction

To determine: Two possible genotypes for a strain of haploid Escherichia coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium.

Introduction: E. coli has a lactose operon, also called the lac operon. It is an inducible operon. This operon helps in the digestion and transportation of lactose. By genetic analysis of the lac operon of E. coli of various mutants, a lot of information has been retrieved.

Explanation of Solution

The lac operon under normal conditions can be represented by the genotype I⁺P⁺O⁺Z⁺ where the Z product will be expressed in the presence of lactose. The I gene represents the repressor gene, P represents the lac promoter gene, O represents the lac operator gene and the Z gene represents the protein product that is formed.

Two possible genotypes for a strain of haploid E. coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium are as follows:

If the I gene has a mutation such that it shows the suppressor genotype, a repressor will be formed in every case. This repressor will bind to the operator in every case, that is whether a lactose inducer is present or absent. Thus, the transcription of the lac genes are suppressed and will never be transcribed. The genotype of such a strain of bacteria can be represented as I^sP⁺O⁺Z⁺.
If the P gene has a mutation, the promoter will be non-functional. When the promoter is non-functional, the RNA polymerase enzyme will not be able to identify the promoter. Thus, the transcription of the lac genes are suppressed and will never be transcribed. The genotype of such a strain of bacteria can be represented as I⁺P^-O⁺Z⁺.

Thus, two possible genotypes for a strain of haploid E. coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium are I^sP⁺O⁺Z⁺ and I⁺P^-O⁺Z⁺.

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Students have asked these similar questions

The streptolysin S toxin made by S. pyogenes is encoded by a 9-gene operon, sagABCDEFGHI. Thinking about what a 3-line diagram would look like for this operon, answer the following questions. Write numeric answers only. For example, if your answer is 6 promoters, write only 6. 1) How many promoters control the expression of these genes? 2) How many locations does RNA Polymerase bind to get full expression of these genes? 3) How many ribosome binding sites are needed for full protein expression? 4) How many start codons will be needed for full protein expression? 5) How many mRNA strands will be produced with full operon expression? 6) How many proteins will be produced with full protein expression? 1

A number of mutations affect the expression of the lac operon in E. coli. The genotypes of several E. coli strains are shown below. ("+" indicates a wild-type gene with normal function and "-" indicates a loss-of-function allele.) Please predict which of the following strains would have the lowest beta-galactosidase enzyme activity, when grown in the lactose medium. Orpt o* z* r* Orpt ot z* Y OrptoztY Orrotzr OrPotz*Y

Suppose that E. coli sustains a mutation in its gene for the lac operon repressor such that the repressor is ineffective. What effect would this have on the bacterium’s ability to catabolize lactose? Would the mutant strain have an advantage over wild-type cells? Explain your answer.

Answer 2

Textbook Question

Chapter 20, Problem 20.1CC

Suppose you are analyzing a haploid E. coli strain and discover that the genes of the lac operon are never transcribed and that the bacteria cannot grow in lactose-containing medium. Provide two possible genotypes for your bacteria that would explain this phenotype.

Expert Solution & Answer

Summary Introduction

To determine: Two possible genotypes for a strain of haploid Escherichia coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium.

Introduction: E. coli has a lactose operon, also called the lac operon. It is an inducible operon. This operon helps in the digestion and transportation of lactose. By genetic analysis of the lac operon of E. coli of various mutants, a lot of information has been retrieved.

Explanation of Solution

The lac operon under normal conditions can be represented by the genotype I⁺P⁺O⁺Z⁺ where the Z product will be expressed in the presence of lactose. The I gene represents the repressor gene, P represents the lac promoter gene, O represents the lac operator gene and the Z gene represents the protein product that is formed.

Two possible genotypes for a strain of haploid E. coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium are as follows:

If the I gene has a mutation such that it shows the suppressor genotype, a repressor will be formed in every case. This repressor will bind to the operator in every case, that is whether a lactose inducer is present or absent. Thus, the transcription of the lac genes are suppressed and will never be transcribed. The genotype of such a strain of bacteria can be represented as I^sP⁺O⁺Z⁺.
If the P gene has a mutation, the promoter will be non-functional. When the promoter is non-functional, the RNA polymerase enzyme will not be able to identify the promoter. Thus, the transcription of the lac genes are suppressed and will never be transcribed. The genotype of such a strain of bacteria can be represented as I⁺P^-O⁺Z⁺.

Thus, two possible genotypes for a strain of haploid E. coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium are I^sP⁺O⁺Z⁺ and I⁺P^-O⁺Z⁺.

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Answer 3

Textbook Question

Chapter 20, Problem 20.1CC

Suppose you are analyzing a haploid E. coli strain and discover that the genes of the lac operon are never transcribed and that the bacteria cannot grow in lactose-containing medium. Provide two possible genotypes for your bacteria that would explain this phenotype.

Expert Solution & Answer

Summary Introduction

To determine: Two possible genotypes for a strain of haploid Escherichia coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium.

Introduction: E. coli has a lactose operon, also called the lac operon. It is an inducible operon. This operon helps in the digestion and transportation of lactose. By genetic analysis of the lac operon of E. coli of various mutants, a lot of information has been retrieved.

Explanation of Solution

The lac operon under normal conditions can be represented by the genotype I⁺P⁺O⁺Z⁺ where the Z product will be expressed in the presence of lactose. The I gene represents the repressor gene, P represents the lac promoter gene, O represents the lac operator gene and the Z gene represents the protein product that is formed.

Two possible genotypes for a strain of haploid E. coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium are as follows:

If the I gene has a mutation such that it shows the suppressor genotype, a repressor will be formed in every case. This repressor will bind to the operator in every case, that is whether a lactose inducer is present or absent. Thus, the transcription of the lac genes are suppressed and will never be transcribed. The genotype of such a strain of bacteria can be represented as I^sP⁺O⁺Z⁺.
If the P gene has a mutation, the promoter will be non-functional. When the promoter is non-functional, the RNA polymerase enzyme will not be able to identify the promoter. Thus, the transcription of the lac genes are suppressed and will never be transcribed. The genotype of such a strain of bacteria can be represented as I⁺P^-O⁺Z⁺.

Thus, two possible genotypes for a strain of haploid E. coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium are I^sP⁺O⁺Z⁺ and I⁺P^-O⁺Z⁺.

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Answer 4

Textbook Question

Chapter 20, Problem 20.1CC

Suppose you are analyzing a haploid E. coli strain and discover that the genes of the lac operon are never transcribed and that the bacteria cannot grow in lactose-containing medium. Provide two possible genotypes for your bacteria that would explain this phenotype.

Expert Solution & Answer

Summary Introduction

To determine: Two possible genotypes for a strain of haploid Escherichia coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium.

Introduction: E. coli has a lactose operon, also called the lac operon. It is an inducible operon. This operon helps in the digestion and transportation of lactose. By genetic analysis of the lac operon of E. coli of various mutants, a lot of information has been retrieved.

Explanation of Solution

The lac operon under normal conditions can be represented by the genotype I⁺P⁺O⁺Z⁺ where the Z product will be expressed in the presence of lactose. The I gene represents the repressor gene, P represents the lac promoter gene, O represents the lac operator gene and the Z gene represents the protein product that is formed.

Two possible genotypes for a strain of haploid E. coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium are as follows:

If the I gene has a mutation such that it shows the suppressor genotype, a repressor will be formed in every case. This repressor will bind to the operator in every case, that is whether a lactose inducer is present or absent. Thus, the transcription of the lac genes are suppressed and will never be transcribed. The genotype of such a strain of bacteria can be represented as I^sP⁺O⁺Z⁺.
If the P gene has a mutation, the promoter will be non-functional. When the promoter is non-functional, the RNA polymerase enzyme will not be able to identify the promoter. Thus, the transcription of the lac genes are suppressed and will never be transcribed. The genotype of such a strain of bacteria can be represented as I⁺P^-O⁺Z⁺.

Thus, two possible genotypes for a strain of haploid E. coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium are I^sP⁺O⁺Z⁺ and I⁺P^-O⁺Z⁺.

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

Summary Introduction

To determine: Two possible genotypes for a strain of haploid Escherichia coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium.

Introduction: E. coli has a lactose operon, also called the lac operon. It is an inducible operon. This operon helps in the digestion and transportation of lactose. By genetic analysis of the lac operon of E. coli of various mutants, a lot of information has been retrieved.

Explanation of Solution

The lac operon under normal conditions can be represented by the genotype I⁺P⁺O⁺Z⁺ where the Z product will be expressed in the presence of lactose. The I gene represents the repressor gene, P represents the lac promoter gene, O represents the lac operator gene and the Z gene represents the protein product that is formed.

Two possible genotypes for a strain of haploid E. coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium are as follows:

If the I gene has a mutation such that it shows the suppressor genotype, a repressor will be formed in every case. This repressor will bind to the operator in every case, that is whether a lactose inducer is present or absent. Thus, the transcription of the lac genes are suppressed and will never be transcribed. The genotype of such a strain of bacteria can be represented as I^sP⁺O⁺Z⁺.
If the P gene has a mutation, the promoter will be non-functional. When the promoter is non-functional, the RNA polymerase enzyme will not be able to identify the promoter. Thus, the transcription of the lac genes are suppressed and will never be transcribed. The genotype of such a strain of bacteria can be represented as I⁺P^-O⁺Z⁺.

Thus, two possible genotypes for a strain of haploid E. coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium are I^sP⁺O⁺Z⁺ and I⁺P^-O⁺Z⁺.

Answer 8

Expert Solution & Answer

Summary Introduction

To determine: Two possible genotypes for a strain of haploid Escherichia coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium.

Introduction: E. coli has a lactose operon, also called the lac operon. It is an inducible operon. This operon helps in the digestion and transportation of lactose. By genetic analysis of the lac operon of E. coli of various mutants, a lot of information has been retrieved.

Explanation of Solution

The lac operon under normal conditions can be represented by the genotype I⁺P⁺O⁺Z⁺ where the Z product will be expressed in the presence of lactose. The I gene represents the repressor gene, P represents the lac promoter gene, O represents the lac operator gene and the Z gene represents the protein product that is formed.

Two possible genotypes for a strain of haploid E. coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium are as follows:

If the I gene has a mutation such that it shows the suppressor genotype, a repressor will be formed in every case. This repressor will bind to the operator in every case, that is whether a lactose inducer is present or absent. Thus, the transcription of the lac genes are suppressed and will never be transcribed. The genotype of such a strain of bacteria can be represented as I^sP⁺O⁺Z⁺.
If the P gene has a mutation, the promoter will be non-functional. When the promoter is non-functional, the RNA polymerase enzyme will not be able to identify the promoter. Thus, the transcription of the lac genes are suppressed and will never be transcribed. The genotype of such a strain of bacteria can be represented as I⁺P^-O⁺Z⁺.

Thus, two possible genotypes for a strain of haploid E. coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium are I^sP⁺O⁺Z⁺ and I⁺P^-O⁺Z⁺.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Summary Introduction

To determine: Two possible genotypes for a strain of haploid Escherichia coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium.

Introduction: E. coli has a lactose operon, also called the lac operon. It is an inducible operon. This operon helps in the digestion and transportation of lactose. By genetic analysis of the lac operon of E. coli of various mutants, a lot of information has been retrieved.

Answer 12

Explanation of Solution

The lac operon under normal conditions can be represented by the genotype I⁺P⁺O⁺Z⁺ where the Z product will be expressed in the presence of lactose. The I gene represents the repressor gene, P represents the lac promoter gene, O represents the lac operator gene and the Z gene represents the protein product that is formed.

Two possible genotypes for a strain of haploid E. coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium are as follows:

If the I gene has a mutation such that it shows the suppressor genotype, a repressor will be formed in every case. This repressor will bind to the operator in every case, that is whether a lactose inducer is present or absent. Thus, the transcription of the lac genes are suppressed and will never be transcribed. The genotype of such a strain of bacteria can be represented as I^sP⁺O⁺Z⁺.
If the P gene has a mutation, the promoter will be non-functional. When the promoter is non-functional, the RNA polymerase enzyme will not be able to identify the promoter. Thus, the transcription of the lac genes are suppressed and will never be transcribed. The genotype of such a strain of bacteria can be represented as I⁺P^-O⁺Z⁺.

Thus, two possible genotypes for a strain of haploid E. coli bacteria in which the genes of the lac operon are never transcribed and the bacteria cannot grow in the lactose-containing medium are I^sP⁺O⁺Z⁺ and I⁺P^-O⁺Z⁺.

Answer 13

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Suppose you are analyzing a haploid E. coli strain and discover that the genes of the lac operon are never transcribed and that the bacteria cannot grow in lactose-containing medium. Provide two possible genotypes for your bacteria that would explain this phenotype .

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