Figure (a) shows three plastic sheets that are large, parallel, and uniformly charged. Figure (b) gives the component of the net electricfield along an x axis through the sheets. The scale of the vertical axis is set by Es = 4.8 × 105 N/C. What is the ratio of the charge densityon sheet 3 to that on sheet 2?Number(a)E (105 N/C)Units3x(b)x

Here's how we can solve it:Step 1: Identify the forces acting on the block:Weight (W): The…

Answered: Figure (a) shows three plastic sheets…

University Physics Volume 2

18th Edition

ISBN:9781938168161

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Chapter6: Gauss's Law

Section: Chapter Questions

Problem 69P: The surface charge density on a long straight metallic pipe is . What is the electric field outside...

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A cylinder of length L=5m has a radius R=2 cm and linear charge density 2=300 µC/m. Although the linear charge density is a constant through the cylinder, the charge density within the cylinder changes with r. Within the cylinder, the charge density of the cylinder varies with radius as a function p( r) =p.r/R. Here R is the radius of the cylinder and R=2 cm and p, is just a constant that you need to determine. b. Find the constant po in terms of R and 2. Then plug in values of R and 1. to find the value for the constant p. c. Assuming that L>>R, use Gauss's law to find out the electric field E inside the cylinder (rR) in terms of 1. and R. d. Based on your result from problem c, find the electric field E at r=1cm and r=4cm.
Positive charge is distributed in a sphere of radius R that is centered at the origin. Inside the sphere, the electric field is Ē(r) = kr-1/4 f, where k is a positive constant. There is no charge outside the sphere. a) How is the charge distributed inside the sphere? In particular, find an equation for the charge density, p. b) Determine the electric field, E(r), for r > R (outside the sphere). c) What is the potential difference between the center of the sphere (r = 0) and the surface of the sphere (r = R)? d) What is the energy stored in this electric charge configuration?
A circular ring of radius 23.0 cm has a continuous charge distribution of -1.4 C/m. How many excess electrons are on the ring? Write your result as multiplicative of 1018. Your result must contain one figure after the decimal point. Maximum of 3% of error is accepted in your answer. One electron charge is -1.6x10 19 C.
The volume charge density ρ for a spherical charge distribution of radius R= 6.00 mm is not uniform. (Figure 1) shows ρ as a function of the distance r from the center of the distribution. a)Calculate the electric field at r = 1.00 mm. b)Calculate the electric field at r = 1.00 mm.
The figure below shows the electric field lines for two charged particles separated by a small distance. (a) Determine the ratio q₁/92. 1/3 X This is the correct magnitude for the ratio. (b) What are the signs of 9₁ and 92? 91 negative 0✓ 92 positive 0✔
You are working as an intern for a meteorological laboratory. You are out in the field taking measurements with a device that measures electric fields. You measure the electric field in the air immediately above the Earth's surface to be 139 N/C directed downward. (Assume the radius of the Earth is 6.37 x 106 m.) (a) Determine the surface charge density (in C/m²) on the ground. C/m? (b) Imagine the surface charge density is uniform over the planet. Determine the charge (in C) of the whole surface of the Earth. (e) Determine the Earth's electric potential (in V) due to the charge found in (b). V (d) Determine the difference in potential (in V) between the head and the feet of a person 1.50 m tall. (Ignore any charges in the atmosphere.) V
The volume charge density ρ for a spherical charge distribution of radius R = 6.00 mm is not uniform. The figure shows ρ as a function of the distance r from the center of the distribution. a) Calculate the electric field at r = 5.00 mm .Express your answer with the appropriate units. b) Calculate the electric field at r = 7.00 mm .Express your answer with the appropriate units
A sphere of radius R has total charge Q. The volume charge density (C/m3) within the sphere is ρ(r)=C/r2, where C is a constant to be determined. a. The charge within a small volume dV is dq=ρdV. The integral of ρdV over the entire volume of the sphere is the total charge Q. Use this fact to determine the constant C in terms of Q and R.Hint: Let dV be a spherical shell of radius r and thickness dr. What is the volume of such a shell? Express your answer in terms of the variables Q and R. b. Use Gauss's law to find an expression for the magnitude of the electric field strength E inside the sphere, r≤R, in terms of Q and R. Express your answer in terms of the variables R, r, Q, and ϵ0.
A circular metal plate of radius 17.2 cm carries a total charge of 1.01 μC and the charge is distributed uniformly over the surface of the plate. Determine the surface charge density on the plate and report your answer in µC/m².
Electric charge is distributed over the triangular region D shown below so that the charge density at (x, y) is o(x, y) = 4xy, measured in coulumbs per square meter (C/m²). Find the total charge on D 1 5 4 3 2 1 7 + coulumbs
A closed surface with dimensions a = b = 0.208 m and c = 0.3328 m is located as in the figure. The electric field throughout the region is nonuniform and defined by E (a + Bx²) î where x is in meters, a = 5 N/C, and 3 = 6 N/(C · m²). Y E Answer in units of C a x k What is the magnitude of the net charge enclosed by the surface? Answer in units of C. part 2 of 2 What is the sign of the charge enclosed in the surface?
A rectangular charged plate with dimensions of a=0.1 m and b=0.4m has a charge density of o = 312 µC /m?. What is the total charge of the plate? Express your answer in units of uC using one decimal point.

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