Find v. (f) in the circuit after t > 0, if vg = 2e-10t Dig 20 ΚΩ Μ 10 ΚΩ Μ 50 με + Δυο
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Find vo (t) in the circuit after t > 0, if ??=2?−10?.
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- 9 62 802 5 mH 一 80V 156 1oov o=t エ has been n positien it moves to position The Switeh n the civauit in for a log time. At +=0 b. Find reltl for t70.The figure shows v(t) and i(t) across a load. Then, the impedance of the load in kQ is: v(t) Volt, i(t) mA -v(t)-it) 250 200 150 100 50 0.dos 0.010 0.015 -50 -100 -150 -200 -250 Time (sec) 1.25Z30° 1.25Z- 45° 1.25Z60° O 1.25Z45°The manimum value of the altenating wotaye and curent are 400 U and 20A respectvely s a cieritoanected to a svita supply . The ristantanerus values of the veltnge and current are 283V and 10 A respectvely of fime t=0, beth icreasing pesitively. 4) Write dan the gapressom for vwltaga and curend at pmet. b). Defermaned tha prver omsumed in the cranit. Take the velye and cunent to be ginusrida). fie P= VI end\ P = YI (PF)
- can you solve this question for value a/4 thenk you :)Determine the value of 'w' in the figure such that the peak value of i(t) is 0.25 A. Use the VR2 + X², identities z = and - jxe - if needed. jwe (1) 100 ww v(t) = 25 cos wt V *0.002 F 6.67 5.02 10.2 None of the answers A Moving to another question will save this response. MacBook Pro 20 47 725 F2 F3 F4 #3 & 2$ 48 % 50 67 ALIn Figure D, what is the value of Rs during the AC signal? 20V 2k0 Rp R100M2 De Ipss 6 mA Vp=-3 V Be = 10 us %3D R315MN R 1502: Cs FIGURE D O 150 2 O 2 kQ O 0Q O infinity
- 2) The Jwitch in the cirant, seca in below has been in pasition a" for a long hime. At t=0, the suitch moves instantancausly to posiñon "b". Find Volt) and iole) for t foma O 30ns biol4) 20ka 5MA Solans toThe Switch sthrown to position 1 Lot t=0 t at t = 500 us, ?+' to pesition 2. întervals f sketch. Ques tion 3 is thrown (do youregs find ilt) for both tronsiont. 1002 50v. 100v O 2H Ans s - 500t ict) = 1-e A. ict.) = 0.5-0.7212 e 5001t-t'} A.e 9:27 E118% ", OON 36 For the following circuit in the figure below. Determine Vp-Va ( in units of V) for ɛ = 47.9 V. a 20 50 Select one: A. 9.58 B. -7.98 C. -39.92 D. -9.58 E. 7.98 Previous page Next page O
- The question is as follows: There are two equations: IL(t) = e-0.599t [0.678 sin (1.3227 ?) + cos (1.3227 ?)] ILnew(t) = -0.774e-5.277t + 1.0744e-0.379t Orange Curve is ILnew Blue curve is IL 2-D) Which equation shows better performance in reaching within 5% of the maximum value? Explain clearlyfor the circuit shown below If v_in=5 sin2m10t then corner frequency will be ......Hz 1 UF 2 k Ohm 1 k Ohim 050 060 070 080 vin1. Find I, VR and Vc. 20 N -j25 N VR 240/30° V