In radishes, the gene controlling color exhibits incomplete dominance. Pure breeding red radishes (genotype RR) crossed with pure breeding white radishes make purple radishes. If a purple radish is crossed with a white radish, - %Rr the genotypes of the progeny will be The phenotypes will be-% purple radishe
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- A is dominant over a and B is dominant over b. Genes A/a and B/b assort independently. The parental cross (P) is between true- breeding (homozygous) strains (AA bb x aa BB). The resulting F1 offspring would be [Select ] A F1 x F1 cross gives the F2 generation. The ratio of phenotypes in the F2 generation can be described as [ Select ] In the phenotypic ratio, what number refers to individuals that are: dominant for both traits? [ Select ] recessive for both traits? [Select ] To what phenotypes do the "3"s in the ratio refer? [ Select ] > >Pea PlantsIn pea plants, a round-seed shape (R) is dominant over a wrinkled-seed shape (r). A round-seeded pea plant was crossed with another round-seeded pea plant. What are the genotype(s) and phenotype(s) ratios of the F1 generation? Show all possibilities using Punnett squares. State the F1 generation genotypes and phenotypes.Bronze coloured turkey is controlled by a dominant allele, B. Red coloured turkey is homozygous for a recessive allele bb. Dominant gene N produce normal feather and recessive genotype produce ‘hairy’ feather nn. In a cross between homozygous bronzed coloured turkey with ‘hairy’ feather and homozygous red coloured turkey with normal feather. What are the ratios of F2 progeny with Bbnn genotypes? (I want to check if what i'm doing is correct)
- Albino rabbits (lacking pigment) are homozygous forthe recessive c allele (C allows pigment formation).Rabbits homozygous for the recessive b allele makebrown pigment, while those with at least one copy ofB make black pigment. True-breeding brown rabbitswere crossed to albinos, which were also BB. F1 rabbits, which were all black, were crossed to the doublerecessive (bb cc). The progeny obtained were 34black, 66 brown, and 100 albino.a. What phenotypic proportions would have beenexpected if the b and c loci were unlinked?b. How far apart are the two loci?n mice, the Ay allele of the agouti gene is recessive lethal, but it is dominant to wild type for yellow coat color. For an unlinked gene called C, cc makes no pigment and are albino while C_ mice will make pigment in in their coat. cc is epistatic to A or AY with regard to coat color, but not for viability. What phenotypic ratio would you expect from the progeny produced by two mice of the genotype: AAy Cc? (Note that “agouti” is the wild-type coat color.) 9 agouti : 3 black : 3 white : 1 yellow 3 agouti : 6 yellow : 3 white 12 yellow : 3 black: 1 brown 9 agouti : 3 yellow : 4 white 8 yellow : 3 black: 1 brownIn Shorthorn cattle, coat color is controlled by a single gene thatcan exist as a red allele (R) or a white allele (r). The heterozygotes (Rr) have a color called roan that looks less red than theRR homozygotes. However, when examined carefully, the roanphenotype in cattle is actually due to a mixture of completelyred hairs and completely white hairs. Should this be calledincomplete dominance, codominance, or something else?Explain your reasoning
- The presence of second allele (E) affects the coat color of Labrador. In particular, the presence of homozygous recessive ee produces yellow Labrador. Supposed a male Lab, homozygous dominant for both alleles, is crossed with a female Lab, homozygous recessive for both alleles, what would be the phenotypic ratio of the F1 offspring?The production of eye-color pigment in Drosophila requires the dominant allele A. The dominant allele P of asecond independent gene turns the pigment to purple,but its recessive allele leaves it red. A fly producing nopigment has white eyes. Two pure lines were crossedwith the following results:P red-eyed female white-eyed maleF1 purple-eyed femalesred-eyed malesF1 F1purple eyed 38red eyed 38white eyed 28F both males and females: 2Explain this mode of inheritance, and show the genotypesof the parents, the F1, and the F2.Tallness (T) in a certain plant is dominant to short (t), while red (R) flower color is dominant to yellow (r). The heterozygous condition results in orange (Rr) flower color. A short plant with red flowers, is crossed with a plant homozygous for tallness and yellow flowers. What would be the genotype and phenotype of the F1 individuals? ttRr—short and orange ttrr—short and yellow TtRr—tall and red Ttrr—tall and yellow TtRr—tall and orange
- Coat color in mice is influenced by two genes, one for color (A) and one for the amount of pigment production (C). Mice with the wild type agouti coat color have a yellowish to brownish color. Mice also have a gene that determines the amount of pigment the hair produces. Mouse Coat Phenotype and Genotype Correlation Agouti coat AA, Aa Solid gray/black coat aa Pigment production CC, Cc Albinism cc Multiple crosses were made between male and female mice that were each heterozygous for both traits (AaCc). The data table shows the number of mice of each coat type. Calculate the average F1 generation coat color to answer the question. Coat Color Number of Mice Born in Each Trial Cross Mean Number of Mice 1 2 3 4 5 6 7 8 9 10 Agouti coat 11 8 9 9 10 8 10 7 10 9 Solid gray/black coat 5 2 1 3 4 3 4 3 3 2 Albinism 3 3 6 4 4 3 3 7 4 3 Which…Heterozygous Cc chickens express a condition called creeper, in which the leg and wing bones are shorter than normal (cc). The dominant C allele is lethal when homozygous. Skin color is determined by the alleles W and w. W_ chickens have white skin and ww chickens have yellow skin. In a mating between 2 chickens heterozygous for both of these genes: 1) What phenotypes will be observed in the progeny? 2) What fraction of the offspring will have each phenotype? Assign alleles. List possible phentoypes. Make gametes, draw Punnett square, and list fractions of genotypes and/or phenotypes of offspring,A recessive epistasis cross gives in the F2 a 9:3:4 phenotypic ratio. What is the expected phenotypic ratio when the F1 (BbEe) is crossed with the double recessive homozygote (bbee)? Keeping in mind ee masks the expression of B.