The 80-kg lamp is supported by two rods AB and BC as shown in Fig. 1-16a O If AB has a diameter of 10 mm and BC has a diameter of 8 mm, determine the average normal stress in each rod. 60° (a) FBA FBC 60 We've updated our read aloud featurel Give It a try here. Co Aa 4) 6:37 PM 2/14/2021

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter8: Centroids And Distributed Loads
Section: Chapter Questions
Problem 8.73P
icon
Related questions
icon
Concept explainers
Question
How did we get Fbc and Fab please explain the simplification
0134321141/cfi/6/32!/4/2/14/12/2/2/4/2@0:0
Mail - Shukry, MX
d VitalSource Bool x
EXAMPLE 1.6
The 80-kg lamp is supported by two rods AB and BC as shown in Fig. 1-16a O. If AB has a diameter of 10 mm and BC has a diameter of 8 mm,
determine the average normal stress in each rod.
60°
(a)
FBA
FBC
60°
B
We've updated our read aloud featurel
Give it a try here.
Copy URL
Aa 4)
6:37 PM
2/14/2021
Transcribed Image Text:0134321141/cfi/6/32!/4/2/14/12/2/2/4/2@0:0 Mail - Shukry, MX d VitalSource Bool x EXAMPLE 1.6 The 80-kg lamp is supported by two rods AB and BC as shown in Fig. 1-16a O. If AB has a diameter of 10 mm and BC has a diameter of 8 mm, determine the average normal stress in each rod. 60° (a) FBA FBC 60° B We've updated our read aloud featurel Give it a try here. Copy URL Aa 4) 6:37 PM 2/14/2021
SOLUTION
Internal Loading.
We must first determine the axial force in each rod. A free-body diagram of the la
equilibrium,
>EF, = 0;
FBC -FBA COS 60° =0
+1EF, = 0;
%3B
FBC)+FBA
sin 60°- 784.8 N = 0
FBA= 632.4 N
FBC = 395.2 N,
By Newton's third law of action, equal but opposite reaction, these forces sub
Transcribed Image Text:SOLUTION Internal Loading. We must first determine the axial force in each rod. A free-body diagram of the la equilibrium, >EF, = 0; FBC -FBA COS 60° =0 +1EF, = 0; %3B FBC)+FBA sin 60°- 784.8 N = 0 FBA= 632.4 N FBC = 395.2 N, By Newton's third law of action, equal but opposite reaction, these forces sub
Expert Solution
Step 1

mass of lamp=80kggravity=9.81 m/s2weight of lamp=m*g  =80*9.81  =784.8Nfree body digram

Mechanical Engineering homework question answer, step 1, image 1

tan θ=34sin θ=35cos θ=4/5

trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Design Against Fluctuating Loads
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
International Edition---engineering Mechanics: St…
International Edition---engineering Mechanics: St…
Mechanical Engineering
ISBN:
9781305501607
Author:
Andrew Pytel And Jaan Kiusalaas
Publisher:
CENGAGE L