1. What is the magnitude of the torque about the origin of the force (-5 î+ 1 Ĵ+ 5 K) N if it is applied at the point whose position vector is 7 = (-27 +41) m. Assume all quantities are correct to 3 significant figures. Enter to 3 significant figures 171 = Nm

College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter7: Rotational Motion And The Law Of Gravity
Section: Chapter Questions
Problem 2WUE: Math Review (a) Convert 47.0 to radians, using the appropriate conversion ratio. (b) Convert 2.35...
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1. What is the magnitude of the torque about the origin of the force
(-5 î+ 1 j+5 K) N
if it is applied at the point whose position vector is
7 = (-27+41) r
m.
Assume all quantities are correct to 3 significant figures.
Enter to 3 significant figures
171 =
Nm
Transcribed Image Text:1. What is the magnitude of the torque about the origin of the force (-5 î+ 1 j+5 K) N if it is applied at the point whose position vector is 7 = (-27+41) r m. Assume all quantities are correct to 3 significant figures. Enter to 3 significant figures 171 = Nm
1. (a) What is the mass of a large ship that has a momentum of 1.11 x 10 kg m/s, when the ship is
moving at a speed of 45.9 km/h?
Enter to 3 significant figures
ms=
✔kg
(b) Compare the ship's momentum to the momentum of a 1.2 x 10³ kg artillery shell fired at a speed
of 1.6 x 10³ m/s.
Assume all quantities are correct to 3 significant figures.
Momentum of the artillery:
Enter to 3 significant figures
Pa
kg m/s
The ratio of the ship's momentum to the momentum of the artillery is:
Enter to 3 significant figures
=
Ps =
Pa
Reflect: Does a large velocity always mean a large momentum? The artillery shell has a large speed
compared to the ship. How does its momentum compare to the ship's moemntum?
Transcribed Image Text:1. (a) What is the mass of a large ship that has a momentum of 1.11 x 10 kg m/s, when the ship is moving at a speed of 45.9 km/h? Enter to 3 significant figures ms= ✔kg (b) Compare the ship's momentum to the momentum of a 1.2 x 10³ kg artillery shell fired at a speed of 1.6 x 10³ m/s. Assume all quantities are correct to 3 significant figures. Momentum of the artillery: Enter to 3 significant figures Pa kg m/s The ratio of the ship's momentum to the momentum of the artillery is: Enter to 3 significant figures = Ps = Pa Reflect: Does a large velocity always mean a large momentum? The artillery shell has a large speed compared to the ship. How does its momentum compare to the ship's moemntum?
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