6.8 k2 1 k2 O +10 V V_ Vo V, 6 -10 V +,
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Plot a graph of the voltage transfer characteristic for the amplifier shown.
Given Inverting operational amplifier
Calculating closed loop voltage gain for inverting amplifier is
Here, voltage at inverting terminal
V_ = 0 V
Range of the output voltage of the op-amp is equal to the power supply voltage +10 V.
For calculating the voltage at inverting terminal V_ disabling the feedback loop at some arbitrary point, so the open loop gain will be zero
A = 0
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- Vc R3 R1 C2 С1 Vin R4 R6 /9441 C3 Vout 01 R2 T2 g160100555 - 987047944 R5 /9447 g160100555- 987047944 R73 C4 VEE Resistance and source g160100555 0100559 g160100555 - 987047944/ •A. ICI =? •b. IC2 =? g160100555- 9870479447 •C. are given below. VCEI =? VCE2 =? 87047944/ For transistors if hFE : •D. g16010055 70/9447 g160100555 R = 87047944 g16010055 87047944/ 100k R3 = 40k R4 = 5k R5 = 20k R6 = 5k R7 = 3k VCC = 15V VEE = -15V 79447 87047944 7944 g160100565 87047944 9441 87047944 9870479447(e) Create a list of components for the following circuit. 6v Vcc D1 R7 4k7 ZS D2 ( M RV1 470k C1 100nF 10µF C2 IC1 R2 150k RS Q4 Q5 Q4-Q14 R5 Q1 Q6 4. Q7 4k7 10 14 13 15 RTC Q8 Q9 4060 Q10 Q12 Q13 Q14 стс R1 100k _12 MR R4 4.7k R6 4.7k LED1 LED2+Vcc V1 5 D2 .tran 10 QTLP690C R8 1k Q4 2N2222 R6 1k vout Q2 2N2222 R2 470 R4 56k C2 HE 47μ VCC C1 47μ Astable Multivibrator R3 56k R1 470 Q1 2N2222 R5 1k D1 QTLP690C R7 1k Q3 2N2222 What is the region of operation of the circuit when the waveform is a. OV b. 4V
- +Vcc V1 5 D2 .tran 10 QTLP690C R8 1k Q4 2N2222 R6 1k vout Q2 2N2222 R2 470 R4 56k C2 HH 47μ VCC C1 H 47μ Astable Multivibrator R3 56k R1 470 Q1 2N2222 R5 1k D1 QTLP690C R7 1k Q3 2N2222 What is the region of operation of the circuit when the waveform is a. OV b. 4VDesign a defferentiator for gven imputsignul and find out the ofp Voltage. Ims 2ms ymsee ams 3ms -2 Vi 3 Scanned by CamScannerVEE -15V 5V Vt R2 D1 D2 R1 5002 1N4001 1N4001 3k2 Find Vt note: show your solutions for each problems.
- How you have find the value of k, Pls expalin in detailIn the circuit shown in the figure, find the equivalent capacity C1 between the A-C points and the equivalent capacity C2 between the B-C points and the C1 / C2 ratio. A 123/149 B 235/249 C 50/89 D 221/200 E 147/245Find the value of IC given that VC = 12 V. Express your answer in kohms. %3D VCC 18V ER1 <4.7kO 5.6k0 31.2ko
- VDD RD RD ID2 Vo ID1 VDD V1 V2 M1 M2 R1 M3 M4 Vss Given VTN=1.5V, Kn=0.1mA/V2, VDD = 10V and Vss = -10V. Find R1 (in kOhms) such that ID2=0.2mA when V1=V2 O 74.3 O 41.3 67.6 O 21.3Plz sir solve this and explain each step properlyQ4) I-V characteristic of solar cell is given in the following figure, use Least Squares Fitting to estimate the general values of a and ß in the characteristic of solar cells 1 =x +ße38.5V. 0.15 0.1 0.05 0. Luylu Voltage (V) Current (A) 0.6-