The enzyme catalase catalyzes the decomposition of hydrogen peroxide: 2 H2O2 ++ 2 H20 + O2 The turnover number (kea) for catalase is 40,000,000 sec-1. The Km of catalase for its substrate H;O, is 0.11 M. (i) In an experiment using 3 nanomole/mL of catalase, what is Vmax? (ii) What is the catalytic efficiency of catalase?

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter13: Chemical Kinetics
Section: Chapter Questions
Problem 13.67QE
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The enzyme catalase catalyzes the decomposition of hydrogen peroxide:
2 H2O2 ++ 2 H20 + O2
The turnover number (kea) for catalase is 40,000,000 sec-1. The Km of catalase for its substrate
H,O, is 0.11 M.
(i)
In an experiment using 3 nanomole/mL of catalase, what is Vmax?
(ii)
What is the catalytic efficiency of catalase?
Transcribed Image Text:The enzyme catalase catalyzes the decomposition of hydrogen peroxide: 2 H2O2 ++ 2 H20 + O2 The turnover number (kea) for catalase is 40,000,000 sec-1. The Km of catalase for its substrate H,O, is 0.11 M. (i) In an experiment using 3 nanomole/mL of catalase, what is Vmax? (ii) What is the catalytic efficiency of catalase?
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