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(a)
Find the drained angle of friction for the silty clay soil.
(a)
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Answer to Problem 12.4P
The drained angle of friction for the silty clay soil is
Explanation of Solution
Given information:
The diameter (d) of clay sample is 63.5 mm.
The height (h) of the clay sample is 32 mm.
Calculation:
Calculate the area of specimen (A) as follows:
Substitute 63.5 mm for d.
Find the normal stress
Here, N is the normal force and A is the area of specimen.
Substitute
Similarly calculate the normal stress
Test no | Normal force, N(N) | Normal stress |
1 | 84 | 26.58 |
2 | 168 | 53.16 |
3 | 254 | 80.38 |
4 | 360 | 113.92 |
Table 1
Find the shear strength
Substitute
Find the angle of friction
Substitute
Similarly calculate the angle of friction
Test no | Shear force, S (N) | Shear strength, | Angle of friction |
1 | 28.9 | 9.14 | 18.97 |
2 | 59.6 | 18.86 | 19.53 |
3 | 89.1 | 28.19 | 19.33 |
4 | 125.3 | 39.65 | 19.19 |
Table 2
Calculate the drained angle of friction
The average value of angle of friction of all tests is the drained angle of friction.
Refer to the Table 2,
Find the drained angle of friction as follows:
Thus, the drained angle of friction for the silty clay soil is
(b)
Find the shear strength of the clay in the field at location A.
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 12.4P
The shear strength of the clay in the field at location A is
Explanation of Solution
Given information:
The specific gravity
The specific gravity
The unit weight
The void ratio (e) is 0.72.
The water content (w) of silty clay is
The depth
The depth
The depth
Calculation:
Calculate the dry unit weight
Substitute 2.69 for
Calculate the saturated unit weight
Substitute 0.72 for e,
Calculate the saturated unit weight
Substitute
Determine the normal stress
Substitute
Find the shear strength
Here,
Substitute
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Chapter 12 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
- A Consolidated-Drained Triaxial Test was conducted on a normally consolidated clay. The results were as follows:· Chamber confining pressure = 400 kPa· Deviator Stress = 600 kPaa. Compute the angle of friction of the clay sample b. Compute the shear stress on the failure planearrow_forward9. A consolidated drained test was carried out on a sandy clay under a cell pressure of 250 kPa. A constant back pressure of 120 kPa applied throughout the test. The dimensions of the sample were 76 mm x 38 mm. Addional test data recorded at failure were: Load transducer force = 368 N 3 Measured change in volume = 2.42 x 10 m³ Axial deformation = 2.05 mm Determine the major principal stress, o, at failure. (455 kPa)arrow_forwardA cu test was performed on a 3.5cm diameter sand sample. A confining pressure of 2.0 kg/cm2 was applied, and the breaking axial load was 45 kg, and the gap water pressure at this time was u=1.0 kg/cm2. 1) What is the effective internal friction angle of this specimen? 2) Evaluate whether the experimental sample is loose/dense. Why? 3) Apply a confining pressure of 1.0 kg/cm2 to this specimen and repeatedly do a cu test. determine the specimen's loose/dense and explain the reason why. (where pressure u = 0.0 kg/cm2) ans is 35 / loose / densearrow_forward
- 6 A consolidated-undrained tri-axial test was conducted on a normally consolidated clay sample and the results are as follows: Chamber confining pressure = 115 kPa, Deviator stress at failure = 87 kPa, Pore Water Pressure = 56 kPa. These results were used to determine the drained friction angle of the soil. Compute the deviator stress (kPa) at failure when the drained test was conducted with the chamber confining pressure changed to 159 kPa. Round off to two decimal places.arrow_forwardQuestion 3 The results of two consolidated-drained test triaxial tests on a clay are given below: Specimen No. Chamber Pressure Deviator Stress 220 400 105 II 210 1. Determine the angle of internal friction. 2. Determine the cohesion of the clay. 3. Determine the normal stress on the point on the failure plane of the 2"d specimen. O Question 1: A. 26.744 O Question 1: B. 26.042 O Question 1: C. 27.871 O Question 1: D. 27.486 O Question 2: A. 10.737 O Question 2: B. 12.141 O Question 2: C. 17.372 O Question 2: D. 14.836 O Question 3: A. 317.694 O Question 3: B. 232.575 O Question 3: C. 230.306 O Question 3: D. 322.194 O O O O O O O COarrow_forwardA consolidated undrained tri-axial test was conducted on a normally consolidated clay sample and the results are as follows: chamber confining pressure = 110kpa deviator stress at failure = 96kpa pore water pressure = 66kpa these test results were used to determine the drained friction angle of the soil. compute the deviator stress in (kpa) at failure when the drained test was conducted with the chamber confining pressure changed to 163kpa.arrow_forward
- A consolidated undrained triaxial test was conducted on a normally consolidated clay sample and the results are as follows: chamber confining pressure = 118 kpa, Deviator stress at failure 93 kpa, pore water pressure = 52 kpa. These results were used to determine the undrained friction angle of the soil. Compute the deviator stress (kPa) at failure when the drain test was conducted in the chamber confining pressure change to 168 kpaarrow_forwardZAIN IQ I. Homework 4... During an oedometer test on a specimen of saturated clay, the thickness of the specimen decreased from 19.931 mm to 19.720 mm under an increment of stress from 200 to 400 kPa which was maintained for 24 hours. The stress was then removed from the specimen, its thickness was measured water content determined as 26.8%. 19.842 mm, and its Taking Gs of the particles to be 2.70, calculate the void ratio before and after the application of the stress increment, and the coefficient of volume decrease (m,) for this stress range. (Ans: e,= 0.731, e2= 0.713, m, = 0.052 m/MN)arrow_forwardA consolidated-drained triaxial test was conducted on an overconsolidated clay sample. The sample failed in test 1 at 01=200 kPa and 03=130 kPa, and in test 2 at o1=400 kPa and 03=290 kPa. Determine the undrained and drained friction angles and cohesion for the assumption that the Skempton's pore water pressure parameter A=0.45. Also, for a CU test on the same soil, determine o1, 1', 03', and excess pore water pressure u for 03=340 kPa.arrow_forward
- A drained triaxial test on the normally consolidated clay showed that the failure plane makes an angle of 58 with the horizontal. If the sample was tested with a chamber confining pressure of 103.5kPA, what was the major principal stress at failure? (Unit in kPa) (Answer only number(whole number without unit)arrow_forwardA) The results of two consolidated-drained triaxial tests on clay are given below in Table 2. Table 2: Results of CDT tests. Specimen Chamber Pressure I II 3, kPa 110 220 Deviator Stress 01-03, kPa 220 400 a) Calculate the shear strength parameters of the soil. b) What are the normal and shear stresses on a plane inclined at 38° to the major principal plane for Specimen I? c) What are the normal and shear stresses on the failure plane at failure for Specimen II? B) The laboratory test results of a standard Proctor test are given in the following table.arrow_forwardA consolidated undrained triaxial test was conducted on a normally consolidated clay. Following are the results of the test: • Cell or Chamber pressure = 200+X kN/m? • Deviator stress at failure = 300+X kN/m? X = 13 a) Determine the consolidated undrained friction angle b) What is the pore water pressure developed in the clay specimen at the end of stage 1 of the test (i.e. consolidation)? c) What is the angle 0 that the failure plane makes with major principal plane? d) Determine the normal stress and shear stress on the failure planearrow_forward
- Principles of Geotechnical Engineering (MindTap C...Civil EngineeringISBN:9781305970939Author:Braja M. Das, Khaled SobhanPublisher:Cengage LearningPrinciples of Foundation Engineering (MindTap Cou...Civil EngineeringISBN:9781337705028Author:Braja M. Das, Nagaratnam SivakuganPublisher:Cengage Learning
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