Solid Waste Engineering
Solid Waste Engineering
3rd Edition
ISBN: 9781305635203
Author: Worrell, William A.
Publisher: Cengage Learning,
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Chapter 3, Problem 3.15P
To determine

The objective function and the constraint equations for minimizing the transportation cost from three collection routes to the two disposal sites.

Expert Solution & Answer
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Answer to Problem 3.15P

The objective function for minimizing the transpiration cost is c=i=13k=12x ikc ik .

The 1st constraint equations are,

x11+x21+x31B1x12+x22+x32B2

The 2nd equations are,

x11+x12=W1x21+x22=W2x31+x32=W3 .

The last constraint equation is xij0 .

Explanation of Solution

Write the expression to obtain the objective function for minimizing the transpiration cost.

c=i=1Nk=1Kx ikc ik ....... (I)

Here, the transportation cost is c , the number of collecting routes in town is N , the number land fill in a community is K, and the cost obtained per quantity of hauling from the source i to the disposal site k is cik .

Substitute 3 for N and 2 for K in Equation (I).

c=i=13k=12x ikc ik

Write the expression for the 1st constraint equation for minimizing the transportation cost.

i=13xikBk ...... (II)

Further solve the above equation.

x11+x21+x31B1x12+x22+x32B2

Here, the above equation signifies that the waste hauled out from each section is less than or equal to the capacity of each of the disposal site.

Write the expression for the 2nd constraint equation for minimizing the transportation cost.

k=12xikWi ...... (III)

Further solve the above equation.

x11+x12=W1x21+x22=W2x31+x32=W3

Here, the above equation signifies that the waste hauled out from each section is equal to the amount generated.

Write the expression for the last constraint equation for minimizing the transportation cost.

xij0

Here, above equation signifies that the waste hauled out from each section must be positive.

Conclusion:

Thus, the objective function for minimizing the transpiration cost is c=i=13k=12x ikc ik .

The 1st constraint equations are,

x11+x21+x31B1x12+x22+x32B2

The 2nd equations are,

x11+x12=W1x21+x22=W2x31+x32=W3 .

The last constraint equation is xij0 .

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