A 1.90 kg box is moving to the right with speed 9.00 m/s on a horizontal, frictionless surface. At t = 0 a horizontal force is applied to the box. The force is directed to the left and has magnitude F(t)=( 6.00 N/s^2 )t2 If the force continues to be applied, what is the velocity of the box at 3.50 s?

A 1.90 kg box is moving to the right with speed 9.00 m/s on a horizontal, frictionless surface. At t = 0 a horizontal force is applied to the box. The force is directed to the left and has magnitude F(t)=( 6.00 N/s^2 )t2 If the force continues to be applied, what is the velocity of the box at 3.50 s?

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter5: Displacement And Force In Two Dimensions

Section: Chapter Questions

Problem 8STP

See similar textbooks

Similar questions

A child with mass of 16.5 kg stands on the edge of a park bench and leaps into the air. Her initial speed is 2.4 m/s directed at an angle of 30 degrees above the horizontal. After 0.28 seconds what is the horizontal component of her velocity in m/s?
A student pushes a 12-kg block on a frictionless, horizontal surface. If the block is initially at rest, what is the speed of the block after the student pushes the block for 5 seconds with an acceleration of 2.0 m/s/s? O 2.0 m/s 6.0 m/s 10 m/s 60 m/s
The block of mass m = 2 kg is released from the rest on the incline. If 0 = 15°, what is the velocity of the block 2 seconds after release? Ms = 0.3, k = 0.20 1.288 m/s 3.084 m/s 2.511 m/s m 0 Ө
A motor exerts F = 20t2 N on the cable which pulls a crate (m = 25 kilos) towards the right. Variable t (time) is in seconds. After 4 seconds, what should be the velocity of the crate? Coefficients for friction are 0.3 (static) and 0.25 (kinetic).
A 10.0-kg box starts at rest and slides 3.5 m down a ramp inclined at an angle of 10° with the horizontal. If there is no friction between the ramp surface and crate, what is the velocity of the crate at the bottom of the ramp? (g = 9.8 m/s2)
An aging coyote (m = 42.1 kg) cannot run fast enough to catch a roadrunner (m = 16.3 kg). He purchases a set of jet-powered roller skates, which proved a constant horizontal acceleration of 15.2 m/s2. The coyote starts at rest 73.2 m from the edge of a cliff at the instant the roadrunner zips past in the direction of the cliff. Hint: their initial positions at the top of the cliff are the same. a. Determine the minimum constant speed the roadrunner must have to reach the cliff before the coyote. b. At the edge of the cliff, the roadrunner escapes by making a sudden turn, while the coyote continues straight ahead. The coyote’s skates remain horizontal and continue to operate while he is in flight, so his acceleration while he is in the air is (15.2i – 9.80j) m/s2. The cliff is 127 m above the flat floor of the desert. Determine how far from the base of the vertical cliff the coyote lands. c. Determine the components of the coyote’s impulse upon impact.
The average thrust created by the first stage engine of a model rocket is 50N. The rocket has an average weight of 10N with a burn time of 2 seconds. The rocket is initially fired vertically upward. When the rocket reaches maximum height, a second engine is fired creating a horizontal velocity (only) of 50m/s. Where does the rocket land relative to its launch point? Assume it was launched on a horizontal plain.
A clever coyote uses rocket powered skates to try to catch a roadrunner. The mass of the coyote is 38.1 kg. If the coyote starts from rest, and accelerates to a final speed of 26 m/s in a distance of 2.4 m, how much thrust force did the rockets excert to get him to his final speed? Assume this thrust is constant over the 2.4 m.
A student launches a small rocket which starts from rest at ground level. At a height of h = 1.8 km the rocket reaches a speed of vf = 342 m/s. At that height the rocket runs out of fuel, so there is no longer any thrust propelling it. Take the positive direction to be upward in this problem B: After the rocket's engine turns off at a height of h = 1.8 km, it continues to move upward due to the velocity that it reached. What is the rocket's acceleration, in meters per second squared, during the period from engine shutoff until it returns to the ground? Ignore air resistance. C: Calculate the maximum height, in meters above ground level, that the rocket reaches.
Sharon pushes a tall box across the floor. Her arms (and therefore her push force) of F = 400 N make a theta= 30 degree angle with the horizontal. Since the box rests on ball bearings it is essentially frictionless. Sick of her job, Sharon decides to give the box a brief shove lasting only t = 0.2 seconds. Find the velocity (magnitude and direction) of the box at the completion of Sharon's shove, assuming (a) the box's weight is 490 N, and (b) the box's weight is 122.5 N. In both cases, the box starts from rest.
A cart of mass 8.00 kg was moved by applying two constant forces. Force 1 is 28.0 N at 42.0°, and Force 2 is 13.0 N at 110°. Initially, the cart has a velocity of (3.50 i +2.20 j) m/s. a. Express the two forces in in unit-vector notation. Ans. F = (20.81 i + 18.74 j)N, F, = (-4.45 i + 12.22 j)N b. Find the total force exerted on the cart. Ans. EF = (16.36 i + 30.96 j)N or 35.02 N Find the angle at which the total force is applied. Ans. 62.15° NEERIN
A cart of mass 8.00 kg was moved by applying two constant forces. Force 1 is 28.0 N at 42.0°, and Force 2 is 13.0 N at 110°. Initially, the cart has a velocity of (3.50 i +2.20 j) m/s. a. Express the two forces in in unit-vector notation. Ans. F = (20.81 i+ 18.74 j)N, F, =(-4.45 i+ 12.22 j)N b. Find the total force exerted on the cart. Ans. EF = (16.36 i + 30.96 j)N or 35.02 N c. Find the angle at which the total force is applied. Ans. 62.15º d. What is the acceleration of the cart? Ans. å = (2.05 i + 3.87 j)" or 4.38 EERIN